Área em Ázul?

\[\frac{((10*10) - (\pi*5^2))}{4}-\frac{\pi(\frac{\sqrt{10^2+10^2}-10}{2})^2}{4}\]

QuartaPartequadradoMenosCirculo =((10*10)-(pi*5^2))/4
QuartaPartequadradoMenosCirculo

## [1] 5.365046

hipotenusa = sqrt(10^2+10^2)
hipotenusa

## [1] 14.14214

diametroMenor = (hipotenusa-10)/2
diametroMenor

## [1] 2.071068

areaCirculoMenor = (pi*diametroMenor^2)/4
areaCirculoMenor

## [1] 3.368826

QuartaPartequadradoMenosCirculo - areaCirculoMenor  

## [1] 1.99622

((10*10) - (pi*5^2))/4 - (pi*((sqrt(10^2+10^2)-10)/2)^2)/4

## [1] 1.99622