Proton NMR, generally referred to as 1H NMR, uses hydrogen nuclei to generate signals between 0 and 12ppm.
An 1H spectra of propanoyl chloride
Similar to how carbons in 13C NMR have different environments, the same hold true in 1H NMR. Different hydrogens can exist within the same environment. The peak area (listed in the diagram under each corresponding peak) is proportional to how many hydrogens exist within that environment. Within actual NMR spectra, the peak area is found by taking the integral l of the range the peak exists in.
The area under the peak, not the height of the peak, shows the density of the environment.
match the above peaks to their corresponding hydrogens based on the peak density.
Despite both the third and fourth carbon having two hydrogen bonds, their hydrogens are not chemically equivilent.
Hydrogen are almost always equivalent to all other hydrogen attached to an atom (ie all four hydrogen in a methane molecule are chemically identical). However, not all similar chemical groups are equivalent
Not all hydrogens with the same chemical structure are chemically equivalent. On the above structure, the far left and far right CH3 groups are not chemically equivalent and therefor have separate peaks on a 1H NMR spectrum.
If Ha and Ha` are chemically equivalent, they have to be bonded to chemically equivalent atoms. The hydrogens on the opposing CH3 are chemically equivalent however the hydrogens on the CH2 are not.
For each of these structures, identify chemically equivalent hydrogens
Splitting in 1H NMR is determined differently than in 13C NMR. The amount of splits is determined by the by the amount of non-equivalent hydrogens within three bonds from the Hydrogen.
Fill in the table describing the relationship between peak multiplicity
and the number of neighboring hydrogens within three bonds
chemical structure and 1H NMR spectrum of propane
The peak cluster at 0.9ppm for propane corresponds to Ha hydrogen atoms. The peak is split twice because within the 3 bond distance, are both of the Hb hydrogen atoms.
The peak cluster at 1.3ppm corresponds to the Hb hydrogen atoms. The peak is split three times despite having 6 hydrogens within the 3 bond distance. this is because both CH3 groups within its range are chemically equivalent and therefor, only one is counted for splitting the peaks.
Similarly to how in 13C NMR, the number of peaks is equal to N+1 where N is the number of bonded hydrogens, in 1H NMR, the number of peaks is equal to N+1 where N is the number of hydrogens within the three bond radius
For each of the molecules above, determine whether the signal from the
circled hydrogen is split by the squared hydrogen. (for the purposes of
this exercise, treat any double or triple bonds the same as a
single)
For each of the molecules above, label each hydrogen atom, giving the
same label to hydrogens in the same environment, then determine for each
hydrogen environment its integration value and its multiplet type
(Remember: integration values are the area under the peak. They are
proportional to the amount of hydrogens in the environment)
below are the most common molecular structures and their corresponding chemical shift (ppm range)
Alcohols do not always follow the rules for predicting multiplicities.
Based on integration and chemical shift alone, assign each of the three peaks in the proton NMR spectrum of ethanol? Which of the peaks above does not follow the peak multiplicity rules we have learned so far?
Which of the above could serve as an NMR solvent?
Using what we know, assign each peak to its hydrogen environment and identify which peaks are caused by the solvent. Does the hydrogen in the alcohol group participate in splitting in this spectrum?
Assign each peak cluster and predict the integration value for each.
The proton NMR data for 1-bromopropane is as follows: H1: triplet (2) 3.2ppm; H2: multiplet (2) 1.81ppm; H3: triplet (3) 0.93ppm. (relative integration value in parentheses) * Draw the structure of 1-bromopropane * According to the splitting rule, does H1 split H3? * How many hydrogens split H2 * Upon closer inspection of of the NMR data, the H2 peak cluster is discovered to have 6 peaks; is this consistent with the answer to the previous question? * Why is any peak cluster with more than four peaks listed as a “multiplet”
Above is the 1H NMR spectrum for C4H8O,
draw a possible structure for this molecule.
Sketch a possible NMR specturm for diethyl ether (CH3CH2OCH2CH3)
Splitting between hydrogens of trans of one another is larger than splitting between hydrogens that are cis of each other.
This can be used to determine whether the molecule is the trans (Z) or cis (E) version of its self
Proton NMR works in much the same way as carbon NMR, but again interpretation of the spectra is a much more important skill for a chemist than understanding the complex physics behind the instrument.
Equivalent H’s do NOT split each other - The rule itself is not hard to follow, but people sometimes forget to check for symmetry and so do not realize that two neighboring H’s are equivalent
Peak area, not peak height, tells you the relative number of H’s associated with a peak cluster - This leaves open the possibility that a tall skinny peak could be smaller (in terms of area) than a short fat peak
Splitting in carbon NMR tells you the number of H’s attached to a given carbon. For this reason, students incorrectly assume that splitting in proton NMR tells you the number of H’s associated with a peak cluster - In fact, it is a bit more complicated
ppm or chemical shift (given by location along the x axis) is a function of the amount of electron density around an H
The closer the H is to an electronegative element, the more “deshielded” it is and therefore the higher the ppm number of its peak cluster (farther left on the spectrum)
Multiple bonds also cause the signal of nearby H’s to be shifted to the left
Each chemically distinct H is expected to have a unique chemical shift, though in practice different peak clusters sometimes overlap just by coincidence - This is a bigger problem in proton NMR than in carbon NMR (especially in the so-called “aromatic region” from 7-9 ppm), since most proton NMR peaks are squeezed into just an 8 ppm range (1-9 ppm)
Integration or peak cluster area (given by a number above or below a peak cluster, or by a line stepping up from left to right called the integration line) tells you the relative area of each peak and therefore the relative number of equivalent H’s represented by each peak
Note that integration (especially the integration line) gives you only a ratio of peak areas - This means the same integration may be reported, for example, on the spectrum of a molecule with 1H to 3H ratio and a 2H to 6H ratio
Multiplicity is the number of peaks in a peak cluster (also called splitting or proton-proton coupling)
It tells you the number of nonequivalent neighbor H’s within three bonds
For example, a doublet (two peaks) tells you there is exactly one non- equivalent H within three bonds of the H responsible for this signal