NMR spectroscopy is a form of spectroscopy that identifies molecules through their reaction to radio waves (100 MHz to 800 MHz). While in the presence of an external magnetic field, 13C atoms will absorb radio wave radiation. NMR machines can measure the exact amount absorbed to determine the environment which the carbon atom is in. Absorbing radiation causes the atom to undergo a “nuclear flip”, thus the name “Nuclear Magnetic Resonance”. NMR is the most widely used tool for determining the structure of molecules.
Five different carbon environments are labeled a - e. Each of the different environments represents how much radiation a given carbon absorbs (measured in ppm). Despite having 7 carbons, the molecule only has five clusters of peaks due to multiple carbons existing in the same environment. Carbons share an environment if their chemical bonds are identical
Next to each carbon in the structure, indicate the number of hydrogens attached to it.
Label each peak cluster with the amount of hydrogen bonds carbons in that environment have.
Explain why the ‘e’ carbons are in a different environment than the ‘d’ carbon.
The three hydrogen atoms attached to the carbon cause the peak generated to split. Splitting shows the possible spins of the hydrogen atoms. the amount of post-split peaks is equal to N+1 where N is the number of bonded hydrgogens.
Hydrogens bonded to carbons can have either a positive or negative spin, the peaks spit in a way to show the probability of a given spin set.
The x axis of the spectrum measures the chemical shift of a carbon environment. Chemical shift (measured in ppm) is equal to the frequency of resonance normalized by the frequency rating of the NMR machine used. This allows machines with different frequency ratings to produce the same chemical shift. The exact ppm of an environment is difficult to predict so they are usually represented in general as a range of values.
The chemical shift of a carbon environment is related to the density of the electron cloud. Therefor, things such as double bonds, and bonds to electron hungry elements effect the ppm of a given carbon environment. These effects are cumulative so a combination of a double bond and a bond to a halogen will both effect the chemical shift
Label each peak with the number of its corresponding atom(s) and
identify the multiplicity of the peak
A decoupled 13C graph of 2-bromobutane
As molecules get more complex, sometimes their peak clusters will overlap, making interpretation very difficult. To deal with this, the graph is decoupled, removing the effects of the hydrogen atoms from the carbons. This turns the peak clusters into singular peaks
Sketch the skeletal structure of 3-methyl-pent-1-ene, then sketch the coupled and decoupled 13C spectrum.
Often in NMR spectra there will be a peak at 0.0ppm and three at 77.00. This is due to the machine reading resonance from additives that act as solutes or as consltants for the machine to tune to. The most common additives are TMS and CDCl_3_
DEPT NMR spectrum of 2-bromobutane
A DEPT spectrum consists of four spectra:
Despite the peaks not being split, the mutliplet type can still be determined based on the layer it appears
Label the peaks on the DEPT spectra with their corresponding carbons (1, 2, 3, or 4)
Which of the carbons does not appear on the DEPT spectra?
What ppm range do you expect carbon 2 to have?
Some two dimensional objects have mirror planes in which a line can be drawn splitting the object into two identical objects.
Draw all lines on symmetry in the following objects
Mark all planes of symmetry on the following molecules
To determine if C_a_ and
C_a_^ are chemically equivalent draw two coppies of the molecule. in the first, replace C~a~ with an X and in the second, replace C_a_^
with an X. Using rotation and mirroring across lines of symmetry, if you
are able to make the two molecules identical, then the two carbons are
chemically equivalent.
The decoupled 13C spectrum for C_6_H_12_ is shown above. Draw
a possible molecular structure that would produce this spectrum.
The 13C spectrum for C5H10O is shown
above. Draw a possible molecular structure that would produce this
spectrum.
The 13C spectrum for another C5H10O
molecule is shown above. This molecule has five carbon environments
instead of the previous molecule’s three. Draw a possible molecular
structure that would produce this spectrum.
NMR (nuclear magnetic resonance) spectroscopy is the most powerful tool that scientists have for looking at the structure of organic molecules
Medicine makes extensive use of this technique–though they drop the word “nuclear” and call it MRI (magnetic resonance imaging)
The physics behind NMR is very complex, although it is essentially similar to other spectroscopy such as IR—except that radio frequency radiation is used instead of infrared light
The very low energy radio waves excite a property called nuclear spin
Though many organic chemists do not have a deep understanding of the theory and physics behind NMR, it is critical that a chemist be an expert at interpreting NMR spectra
Interpretation of a (decoupled) carbon NMR spectrum involves two variables: number of peaks, and peak location
The challenge is figuring out how many peaks are expected for a candidate structure; in other words, figuring out which carbons are unique and which carbons are equivalent
The two key tools for this are identifying mirror planes and visualizing the molecule in motion
ppm or chemical shift
If a C is close to an electronegative element or involved in a multiple bond, or both, you will find the corresponding peak at higher ppm (farther left on the spectrum)
Each chemically distinct C should have a unique chemical shift, though in practice different peak clusters sometimes overlap just by coincidence - this can make interpretation of coupled spectra very difficult, which is why decoupled spectra are usually taken
You do not need to know the exact ppm value associated with a carbon on a given structure - You need only know the ppm ranges for common types of carbon atoms
Peaks
Peak height is not a reliable measure of the number of carbons of a given type in C-13 NMR
Multiplicity in a proton-coupled 13C NMR spectrum tells you the number of H’s attached to a given carbon - For example, a C that produces a doublet must have one H attached to it
Coupling
Very often chemists record “proton-decoupled” 13C NMR spectra - Such spectra have a singlet for each chemically unique carbon. This is useful for complex molecules for which the peak clusters would overlap
A decoupled 13C NMR spectrum tells you the number of different carbon atoms present in the sample, but not the multiplicity - This is where a DEPT spectrum can be very useful as it tells you the multiplicity of each peak appearing on the 13C NMR spectrum
DEPT spectra do not include singlets - this means it is usually necessary to use a DEPT in conjunction with an ordinary 13C NMR spectrum
Using the DEPT, you can assign each peak on the ordinary 13C NMR spectrum as a singlet, doublet, triplet, or quartet
Keep in mind that an NMR spectrum is a “snapshot” of the molecule over a number of seconds
Molecular motion such as rotation about single bonds gets averaged
This means the OH group in phenol does not break the symmetry of the molecule