From Ch9.2, we learned that
\[ Q = cm\frac{dU}{dt} \]
Newton's Law of Cooling: \( Q \) is proportional to the temperature difference between the object and its surroundings:
\[ \frac{dU}{dt} = -\frac{hS}{cm} \left( U(t) - u_s \right) \]
What did the fish say when he hit the wall?
Dam.
In the compartment diagram below, equilibrium temperature corresponds to heat outflow and heat inflow being the same.
\[ \begin{Bmatrix} \mathrm{rate \, of \, change} \\ \mathrm{of \, heat ~ content } \end{Bmatrix} = 0 \]
\[ J = \begin{Bmatrix} \mathrm{rate \, of \, flow ~ of ~ heat} \\ \mathrm{per ~unit ~ time ~ per \, unit ~ area } \end{Bmatrix} \]
Heat flux is proportional to gradient of temperature as a function of distance \( x \).
\[ J(x) = -k \frac{dU}{dx} \]
Need minus sign for positive rate of heat conduction:
\[ J(x) = -k \frac{dU}{dx} \]