5 July 2015
We can't measure it. It's a one-off event.
What odds are you willing to bet that Labor will win?
\(P(A|B) = P(A&B)/P(B)\)
You meet a proud mother of two children whose eldest is a girl. What's the probability that the youngest child is a girl?
You meet another proud mother of two children. You ask her if at least one of her children is a girl, and she says yes. What's the probability that both children are girls?
You meet a yet another proud mother of two children. She brings one of them along at random to a party you throw. You greet the proud mother and her daughter warmly when they visit. What's the probability that both of her children are girls?
Suppose a mother of two children is on a game show, and she's given the choice of three doors: Behind one door is a car; behind the others, goats. She picks a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to her, "Do you want to pick door No. 2?" Is it to her advantage to switch her choice?
What's the probability of winning if she switches?
\(P(\text{Cancer} | \text{Positive}) = \frac{P(\text{Positive} | \text{Cancer}) P(\text{Cancer})}{P(\text{Positive})}\)
\(\tiny{P(Positive) = P(Positive|Cancer) P(Cancer) + P(Positive | No Cancer)P(No Cancer)}\)
\(P(Cancer | Positive) = \frac{80\% \times 1\%}{80\% \times 1\% + 9.6\% \times 99\%} = 7.76\%\)
\(P(\text{H} | \text{E}) = \frac{P(\text{E} | \text{H}) P(H) }{P(\text{E})}\)
\({P(E) = P(E | H1) P(H1) + P(E | H2) P(H2) + \ldots}\)
These equations are used as the basis for Bayesian Statistics.
John is a man who wears gothic inspired clothing, has long black hair, and listens to death metal. How likely is it that he is a Christian and how likely is it that he is a Satanist?
Use reference class forecasting:
In the real world, there are no certainties, only probabilities.