For hierachical clustering and exploratory data analysis read Chapter 12 “Cluster Analysis” from An Introduction to Statistical Learning with Applications in R by Gareth James, Daniela Witten, Trevor Hastie and Robert Tibshirani - reading (p.385-p.399).
Remember this is just a starting point, explore the reading list, practical and lecture for more ideas.
Reference: Gareth James, Daniela Witten, Trevor Hastie and Robert Tibshirani 2013.An Introduction to Statistical Learning with Applications in R. https://faculty.marshall.usc.edu/gareth-james/ISL/ISLR%20Seventh%20Printing.pdf
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library(readr)
mydata <-read_csv('customer_segmentation.csv')
## Rows: 71 Columns: 3
## ── Column specification ────────────────────────────────────────────────────────
## Delimiter: ","
## dbl (3): tiktok_use, recommendations, purchase_tiktok
##
## ℹ Use `spec()` to retrieve the full column specification for this data.
## ℹ Specify the column types or set `show_col_types = FALSE` to quiet this message.
In the following step, you will standardize your data(i.e., data with a mean of 0 and a standard deviation of 1). You can use the scale function from the R environment which is a generic function whose default method centers and/or scales the columns of a numeric matrix.
Hierarchical clustering (using the function hclust) is an informative way to visualize the data.
We will see if we could discover subgroups among the variables or among the observations.
use = scale(mydata[,-c(1)], center = TRUE, scale = TRUE)
dist = dist(use)
d <- dist(as.matrix(dist)) # find distance matrix
seg.hclust <- hclust(d) # apply hirarchical clustering
library(ggplot2) # needs no introduction
plot(seg.hclust)
Imagine if your goal is to find some profitable customers to target. Now you will be able to see the number of customers using this algorithm.
groups.3 = cutree(seg.hclust,3)
table(groups.3) #A good first step is to use the table function to see how # many observations are in each cluster
## groups.3
## 1 2 3
## 28 38 5
#In the following step, we will find the members in each cluster or group.
mydata$ID[groups.3 == 1]
## Warning: Unknown or uninitialised column: `ID`.
## NULL
mydata$ID[groups.3 == 2]
## Warning: Unknown or uninitialised column: `ID`.
## NULL
mydata$ID[groups.3 == 3]
## Warning: Unknown or uninitialised column: `ID`.
## NULL
#?aggregate
aggregate(mydata,list(groups.3),median)
## Group.1 tiktok_use recommendations purchase_tiktok
## 1 1 2 7 1
## 2 2 2 1 NA
## 3 3 NA 2 6
aggregate(mydata,list(groups.3),mean)
## Group.1 tiktok_use recommendations purchase_tiktok
## 1 1 2.500000 6.071429 1.607143
## 2 2 2.605263 1.289474 NA
## 3 3 NA 2.600000 6.000000
aggregate(mydata[,-1],list(groups.3),median)
## Group.1 recommendations purchase_tiktok
## 1 1 7 1
## 2 2 1 NA
## 3 3 2 6
aggregate(mydata[,-1],list(groups.3),mean)
## Group.1 recommendations purchase_tiktok
## 1 1 6.071429 1.607143
## 2 2 1.289474 NA
## 3 3 2.600000 6.000000
cluster_means <- aggregate(mydata[,-1],list(groups.3),mean)
write.csv(groups.3, "clusterID.csv")
write.csv(cluster_means, "cluster_means.csv")
First, select the files (“clusterID.csv” & “cluster_means.csv”) and put a checkmark before each file.
Second, click the gear icon on the right side of your pane and export the data.
Imagine if your goal is to find some profitable customers to target. Now using the mean function or the median function, you will be able to see the characteristics of each sub-group. Now it is time to use your domain expertise.
How many observations do we have in each cluster? Answer: Your answer here:
We can look at the medians (or means) for the variables in each cluster. Why is this important?
Answer: Your answer here:
Answer: Your answer here:
Answer: Your answer here:
Any major differences between K-means clustering (https://rpubs.com/utjimmyx/kmeans) and Hierarchical clustering? Which one do you like better? Why? You may refer to the assigned readings.
Do a keyword search using “cluster analysis.” How many relevant job titles are there?
Answer: Your answer here:
O. The aggregate function is well suited for this task. Should we use mydata or mydata[,-1] along with the aggregate function? Why? Hint: see the results of my tutorial.