Aria Cederlof, Kepuali Otuafi, Addison Scanlon, and Kenan Ince
November 21, 2021
We used a \( \chi^{2} \) model with \( 4-1=3 \) degrees of freedom. The three conditions that must be checked are:
# A tibble: 1 × 4
statistic p.value parameter method
<dbl> <dbl> <dbl> <chr>
1 2237. 0 3 Chi-squared test for given probabilities
The value of our 2014 \( \chi^{2} \) is 2237.4214612 with a \( p \)-value of less than \( 0.0001 \). We reject the null hypothesis of no difference in racial demographics. There is statistically significant evidence that the distribution of races against whom SLCPD used force is different from the distribution of races in Salt Lake City.
race_2014
Asian or Pacific Islander Black Indigenous
-16.033295 34.054482 27.916891
White
-6.426069
# A tibble: 1 × 4
statistic p.value parameter method
<dbl> <dbl> <dbl> <chr>
1 3196. 0 3 Chi-squared test for given probabilities
The value of our \( \chi^{2} \) is 3196.2268752. The \( p \)-value is less than \( 0.001 \). We reject the null hypothesis of no racial differences in use of force.
The value of our \( \chi^{2} \) is 46.7187277. The \( p \)-value is 3.9889362 × 10-10.
The p-value calculated is exceptionally small, meaning that we reject the null in favor of the alternative hypothesis. This means that there is significant evidence that the proportions of races in our data is not equal to the model proportions in the American Community Survey.
The value of our \( \chi^{2} \) is 857.9825016. The \( p \)-value is 1.1498775 × 10-185.
The p-value calculated is exceptionally small, meaning that we reject the null in favor of the alternative hypothesis. This means that there is significant evidence that the proportions of races in our data is not equal to the model proportions in the American Community Survey.
Any questions?