Stats scores. (2.33, p. 78) Below are the final exam scores of twenty introductory statistics students.
57, 66, 69, 71, 72, 73, 74, 77, 78, 78, 79, 79, 81, 81, 82, 83, 83, 88, 89, 94
Create a box plot of the distribution of these scores. The five number summary provided below may be useful.
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 57.00 72.75 78.50 77.70 82.25 94.00
Mix-and-match. (2.10, p. 57) Describe the distribution in the histograms below and match them to the box plots.
The distribution in the histograms with matching box plots are as follows: Histogram A, is a unimodal distribution (has one prominent peak) and match box plot #2 Histogram B, is a multimodal distribution (has more than two prominent peaks) and match box plot #3 Histogram C, is a bimodal distribution (has two peaks) and match box plot #1
Distributions and appropriate statistics, Part II. (2.16, p. 59) For each of the following, state whether you expect the distribution to be symmetric, right skewed, or left skewed. Also specify whether the mean or median would best represent a typical observation in the data, and whether the variability of observations would be best represented using the standard deviation or IQR. Explain your reasoning.
**Response (a)
The distribution of the data will be a strong left skewed histogram and the median house cost will be the best representation for this observational data. To show the variability of the observations the IQR calculation should be used because the number of houses that cost more than $6,000,000 extends beyond the 75th percentile and very distant from most of the data.**
**Response (b)
The distribution of the data will be left skewed and the mean house cost will be the best representative for this observational data. To show the variability of the observations the standard deviation should be used because houses that cost more than $1,200,000 is within range and inside the maximum observed values.**
**Response (c)
The distribution of the data will be symmetric and the mean will be the best representative for this observational data. To show the variability of the observations the standard deviation should be used because the consumption of drinks will peak after the initial and reduce at the due to implementing moderation or limitations to focus on school courses.**
**Response (d)
The distribution of the data will be a strong right skewed histogram and the median annual salaries will be the best representation for this observational data. To show the variability of the observations the IQR calculation should be used because the high level executives much higher salaries will negatively affect the range of the other employees.
Heart transplants. (2.26, p. 76) The Stanford University Heart Transplant Study was conducted to determine whether an experimental heart transplant program increased lifespan. Each patient entering the program was designated an official heart transplant candidate, meaning that he was gravely ill and would most likely benefit from a new heart. Some patients got a transplant and some did not. The variable transplant indicates which group the patients were in; patients in the treatment group got a transplant and those in the control group did not. Of the 34 patients in the control group, 30 died. Of the 69 people in the treatment group, 45 died. Another variable called survived was used to indicate whether or not the patient was alive at the end of the study.
Response (a)
The mosaic plot shows that survival is dependent on whether or not the patient got a transplant.
Response (b)
The plot box suggest the treatment group had more alive cancer patients than the control group.
What proportion of patients in the treatment group and what proportion of patients in the control group died?
One approach for investigating whether or not the treatment is effective is to use a randomization technique.
Response (d.i): The claims being tested are (1) whether a heart transplant will increase lifespan and (2) the study results will indicate a dependency model.
We write alive on 28 cards representing patients who were alive at the end of the study, and dead on 75 cards representing patients who were not. Then, we shuffle these cards and split them into two groups: one group of size _53____ representing treatment, and another group of size ____50____ representing control. We calculate the difference between the proportion of dead cards in the treatment and control groups (treatment - control) and record this value. We repeat this 100 times to build a distribution centered at 1.08_. Lastly, we calculate the fraction of simulations where the simulated differences in proportions are _-0.016______. If this fraction is low, we conclude that it is unlikely to have observed such an outcome by chance and that the null hypothesis should be rejected in favor of the alternative.
Response (d.iii)
The simulation results shows the cancer patients in treatment had a greater rate of living than the control group.
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