Homework 1

Given Data

Machine1<-c(16.03,16.04,16.05,16.05,16.02,16.01,15.96,15.98,16.02,15.99)
Machine2<-c(16.02,15.97,15.96,16.01,15.99,16.03,16.04,16.02,16.01,16.00)

A<-cbind(Machine1,Machine2)

Finding out the Mean

summary(Machine1)

##    Min. 1st Qu.  Median    Mean 3rd Qu.    Max. 
##   15.96   15.99   16.02   16.02   16.04   16.05

summary(Machine2)

##    Min. 1st Qu.  Median    Mean 3rd Qu.    Max. 
##   15.96   15.99   16.01   16.00   16.02   16.04

Runninng T-Test

t.test(Machine1,Machine2,var.equal = TRUE)

## 
##  Two Sample t-test
## 
## data:  Machine1 and Machine2
## t = 0.79894, df = 18, p-value = 0.4347
## alternative hypothesis: true difference in means is not equal to 0
## 95 percent confidence interval:
##  -0.01629652  0.03629652
## sample estimates:
## mean of x mean of y 
##    16.015    16.005

As the p value is greater than alpha i.e. 0.05 hence we failed to reject null hypothesis