\[n= 16 \\ \alpha= 0.05 \\ \overline {x}_1= 19.6 \\ \overline {x}_2= 20.2 \\ s_1= 0.4 \\ s_2= 0.6\]
First we need to establish our null and alternative hypothesis. Since we are trying to figure out if the mileage of B significantly better than that of A, our null hypothesis is when μ1 is equals to μ2. On the other hand, the alternative hypothesis is when μ1 is less than μ2.
\[H_0: \mu_1 = \mu_2 \\ H_1: \mu_1 < \mu_2\]
Next we will figure out what test statistic to use. We will use this formula:
\[ Z_0 = \frac{(\overline {x}_1 - \overline {x}_2)} {\sqrt{{\frac {s_1^2}{n_1} + \frac {s_2^2}{n_2} }}} \]
Inputting the values into the formula,
\[ Z_0 = \frac{(19.6 - 20.2)} {\sqrt{{\frac {0.4^2}{16} + \frac {0.6^2}{16} }}} \\ = \frac{-0.6}{\frac {\sqrt{13}}{20}} = -3.282 ≈ -3.33\]
Since we are given the significance level of a= 0.05, the critical value is t= -1.7 according to the t table. We can see that the test statistic is less than the critical value.
\[-3.33 < -1.7\]
Now, we will also look for the p-value to further confirm our conclusions.
\[ 1 - 0.999566 = 0.000434 \\ 0.000454 < \alpha\]
Final answer: With all of this, we must reject Ho. We can then conclude that the mileage of B is significantly better than that of A.
(Used these cheatsheets to code the equations, formulas, and solutions)
[1] N. Tierney, “RMarkdown for Scientists,” 11 Math, 09-Sep-2020. [Online]. Available: https://rmd4sci.njtierney.com/math.
[2] R. Pruim, Mathematics in R Markdown, 19-Oct-2016. [Online]. Available: https://rpruim.github.io/s341/S19/from-class/MathinRmd.html.