Using the “cars” dataset in R, build a linear model for stopping distance as a function of speed and replicate the analysis of your textbook chapter 3 (visualization, quality evaluation of the model, and residual analysis.)
## Structure of Daataset: cars
## 'data.frame': 50 obs. of 2 variables:
## $ speed: num 4 4 7 7 8 9 10 10 10 11 ...
## $ dist : num 2 10 4 22 16 10 18 26 34 17 ...
##
## Summary of cars
## speed dist
## Min. : 4.0 Min. : 2.00
## 1st Qu.:12.0 1st Qu.: 26.00
## Median :15.0 Median : 36.00
## Mean :15.4 Mean : 42.98
## 3rd Qu.:19.0 3rd Qu.: 56.00
## Max. :25.0 Max. :120.00
##
## We can see that there is a record showing maximum speed of 25 for a stopping distance of 120
## `geom_smooth()` using formula 'y ~ x'
##
## There is definitely a linear pattern between stopping distance and speed.
##
## Linear Model Parameters
##
## Call:
## lm(formula = dist ~ speed, data = cars)
##
## Residuals:
## Min 1Q Median 3Q Max
## -29.069 -9.525 -2.272 9.215 43.201
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) -17.5791 6.7584 -2.601 0.0123 *
## speed 3.9324 0.4155 9.464 1.49e-12 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 15.38 on 48 degrees of freedom
## Multiple R-squared: 0.6511, Adjusted R-squared: 0.6438
## F-statistic: 89.57 on 1 and 48 DF, p-value: 1.49e-12
##
## The equation of the linear model is : Stopping distance= 3.9324*speed -17.5791, b or y-intercept = -17.5791, slope or a-coeficient = 3.9324, there is normally an error since the linear model isn;t 100% fit.
##
## Linear Model Validation
##
## Nearly Normal Residuals
##
## The following function calls produce the residuals plot for our model.
##
## The Q-Q plot provides a nice visual indication of whether the residuals from the model are normally distributed.
##
## There are some outliers in the data but the linear model is validated as error aren't significant