Continuous probability distributions vary by the shape under the curve.
The normal distribution is not only symmetrical, but bell-shaped, a shape that (loosely) suggests the profile of a bell. Being bell-shaped means that most values of the continuous vari- able will cluster around the mean.
It is also known as rectangular distribution, contains the values that are equally distributed in the range between the minimum value and the maximum value. In a uniform distribution every value has a equal chance of occurrence
The exponential distribution contains values from zero to positive infinity and is right-skewed, making the mean greater than the median
\(\large f(x) = \frac{1}{\sigma\sqrt{2\pi}}e^-(\frac{1}{2})(\frac{x-\mu}{\sigma})^2\)
where,
e = mathematical constant (2.71828)
\(\pi\) = mathematical constant (3.14159)
\(\mu\) = mean
\(\sigma\) = standard deviation
X = Any value of the continuous variable, \(-\infty < X < \infty\)
To compute Normal probabilites, you need to first convert X to a standardized normal variable (Z), using Transformation formula
The Z value is equal to difference between X and the mean,\(\mu\), divided by the standard deviation(\(\sigma\))
\(\text{Z =} \large \frac{x-\mu}{\sigma}\)
1-pnorm(9,7,2)
## [1] 0.1586553
pnorm(7,7,2) + (1-pnorm(9,7,2))
## [1] 0.6586553
qnorm(0.10,7,2)
## [1] 4.436897
Thus, 10% of the load times are 4.44 seconds or less
Construct charts and observe their appearance. For small or moderate sized data sets, create a stem-and-leaf display or a boxplot. For large data sets, in addition, plot a histogram or polygon.
Compute descriptive statistics and compare these statistics with the theoretical proper- ties of the normal distribution. Compare the mean and median. Is the interquartile range approximately 1.33 times the standard deviation? Is the range approximately 6 times the standard deviation?
Evaluate how the values are distributed. Determine whether approximately two-thirds of the values lie between the mean and \(\pm\) 1 standard deviation. Determine whether approximately four-fifths of the values lie between the mean and \(\pm\) 1.28 standard deviations. Determine whether approximately 19 out of every 20 values lie between the mean and \(\pm\) 2 standard deviations.
In the uniform distribution, the values are evenly distributed in the range between the smallest value, a, and the largest value, b.
Because of its shape, the uniform distribution is sometimes called the rectangular distribution
Uniform Probability Density Function
\(\large f(x) = \Large \frac{1}{b-a}, \normalsize \text{if a} \le \text{X} \le b \land \text{0 elsewhere}\)
where,
a = minimum value of X
b = maximum value of X