We often don’t root phylogenetic trees. This reduces the number of possible trees and is described by the equation:
Text: (2n-5)!/[2n-3*(n-3)!]
Rendered:
\(\frac{(2*n-5)!}{2^{n-3} * (n-3)!}\)
Modify the function used in the “number of phylogenetic trees” tutorial to work for unrooted trees.
Compare your results to http://carrot.mcb.uconn.edu/mcb396_41/tree_number.html
You can use the simplest form of the function which doesn’t have any additional argument, eg
The function is here; make the necessary changeas
# change the code below to work for an un-rooted tree
tree_count <- function(n = 3){
# change the denominator if need
numerator <- factorial(2*n-5)
# change the denominator if needed
denominator <- 2^(n-3)*factorial(n-3)
trees <- numerator / denominator
print(trees)
}
Create a function that will work for rooted OR unrooted trees. Do this by adding an additional argument like
type = “rooted”
and conditional additional statements like
if(type == "rooted){ #do this }
if(type == "unrooted){ #do something else }
Again, you can use the simplest form of the argument.
tree_count <- function(n,
type,
format = "standard"){
if(n<2){
warning("This function is only valid for 2 or more taxa.")
}
if(format %in% c("sci", "scientific", "e")){
options(scipen = -2, digits =3)
}
if(type=="rooted"){
numerator <- factorial(2*n-3)
denominator <- 2^(n-2)*factorial(n-2)
trees <- numerator / denominator
}
if(type=="unrooted"){
numerator <- factorial(2*n-5)
denominator <- 2^(n-3)*factorial(n-3)
trees <- numerator / denominator
}
print(trees)
}
For this assignment, render to RRubps, submit the link, and submit a screen grab that contains