Choose independently two numbers B and C at random from the interval [0, 1] with uniform density. Prove that B and C are proper probability distributions.
Note that the point (B,C) is then chosen at random in the unit square.
Find the probability that
B + C < 1/2
B + C = 1 passes through the points (1/2, 0) and (0, 1/2).
==> B + C < 1 is the area of the triangle formed in the unit square and the half plane B + C < 0.5
==> So, P(B + C) = (Area of triangle with vertices (1/2, 0), (0, 1/2), (0, 0))
==> (1/2) * (1/2)(1/2) = 1/8
BC < 1/2
==> P(BC < 1/2)
==> ∫(x = 1/2 to 1) dx/(2x) = (1/2) ln 2
|B − C| < 1/2
==> P(B >= 1/2 + C, C < 1/2 ) + P(C >= 1/2 + B, B < 1/2 )
==> P(B > 1/2 , C < 1/2) + P(C > 1/2, B < 1/2)
==> B < 1/2 or B > 1/2 occurs half the time, so the probability is 1/2
==> C < 1/2 or C > 1/2 occurs half the time, so the probability is 1/2
==> 1/2 + 1/2 = 1/4
max{B,C} < 1/2
==> Means P(B < 1/2) and P(C < 1/2)
==> B < 1/2 occurs half the time, so the probability is 1/2
==> C < 1/2 occurs half the time, so the probability is 1/2
==> 1/2 x 1/2 = 1/4
min{B,C} < 1/2
==> Means P(B < 1/2) or P(C < 1/2)
==> B < 1/2 occurs half the time, so the probability is 1/2
==> C < 1/2 occurs half the time, so the probability is 1/2
==> 1/2 or 1/2 = 1/2