Title: (From AGU) Using continuous sap flux and soil respiration datasets to infer the strength and speed of root-soil coupling in a deciduous forest
Authors: Stephanie C. Pennington, Ben Bond-Lamberty, Charlotte Grossiord, Wenzhi Wang, Nate McDowell
Target Journal:
Overall Scientific Question: What is strength and speed of above-belowground coupling (Js to Rs)?
Arrows indicate the direction of the loop
Split by daytime and nighttime values
The partial autocorrelation function gives the partial correlation (i.e. after controlling for other variables, or in this case, time lags) of a stationary time series with its own lagged values.
We expect to see changes in the strength and speed of coupling, probably because of seasonal changes in photosynthetic capacity and carbon allocation (e.g. reflected in stem diameter growth data).
If H1.1 is correct, then days with more sunlight would have a stronger correlation.
To examine this issue, we look at matched days, i.e. that are in the same part of the growing season and have similar conditions EXCEPT for sunlight.
Goal: To compare Rs:Js correlation of sunny vs. cloudy days. We essentially are testing the importance of PAR on the relationship.
We’ve created a function similar_days to match days of similar climate conditions but varying PAR (i.e. sunny-cloudy days)
First, we tested how the constraints for climate conditions impacted the number of matches returned
| Constraint | max | min | sd | Constraint value |
|---|---|---|---|---|
| Precip | 1.375 | 0.000 | 0.198 | NA |
| RH | 98.509 | 19.829 | 16.466 | 10.0 |
| SM | 0.494 | 0.144 | 0.075 | 0.2 |
| T5 | 26.039 | 0.617 | 7.954 | 2.0 |
| Tair | 32.382 | -9.768 | 9.579 | 2.0 |
| VPD | 1.712 | 0.014 | 0.342 | 0.5 |
| Lookahead | NA | NA | NA | 10.0 |
Differences in daily means between sunny and cloudy days? We use a paired (because we have matched days) Student’s t-test for this.
## Js_avg:
##
## Paired t-test
##
## data: tt_js$Cloudy and tt_js$Sunny
## t = -2.5667, df = 26, p-value = 0.01638
## alternative hypothesis: true difference in means is not equal to 0
## 95 percent confidence interval:
## -3.117715e-06 -3.447635e-07
## sample estimates:
## mean of the differences
## -1.731239e-06
## Rs_avg:
##
## Paired t-test
##
## data: tt_js$Cloudy and tt_js$Sunny
## t = 2.5345, df = 43, p-value = 0.01498
## alternative hypothesis: true difference in means is not equal to 0
## 95 percent confidence interval:
## 0.1188971 1.0449492
## sample estimates:
## mean of the differences
## 0.5819232
Matched days by Tree (columns) and day of the year of the sunny day (rows). Sunny days are shown in blue with it’s cloudy matches in red.
Matched days by day of the year of the sunny day. Sunny days are shown in blue with it’s cloudy matches in red.