The objectives of this problem set is to orient you to a number of activities in R. And to conduct a thoughtful exercise in appreciating the importance of data visualization. For each question create a code chunk or text response that completes/answers the activity or question requested. Finally, upon completion name your final output .html file as: YourName_ANLY512-Section-Year-Semester.html and upload it to the “Problem Set 2” assignment to your R Pubs account and submit the link to Moodle. Points will be deducted for uploading the improper format.
anscombe data that is part of the library(datasets) in R. And assign that data to a new object called data.data=anscombe
data
## x1 x2 x3 x4 y1 y2 y3 y4
## 1 10 10 10 8 8.04 9.14 7.46 6.58
## 2 8 8 8 8 6.95 8.14 6.77 5.76
## 3 13 13 13 8 7.58 8.74 12.74 7.71
## 4 9 9 9 8 8.81 8.77 7.11 8.84
## 5 11 11 11 8 8.33 9.26 7.81 8.47
## 6 14 14 14 8 9.96 8.10 8.84 7.04
## 7 6 6 6 8 7.24 6.13 6.08 5.25
## 8 4 4 4 19 4.26 3.10 5.39 12.50
## 9 12 12 12 8 10.84 9.13 8.15 5.56
## 10 7 7 7 8 4.82 7.26 6.42 7.91
## 11 5 5 5 8 5.68 4.74 5.73 6.89
fBasics() package!)summary(data)
## x1 x2 x3 x4 y1
## Min. : 4.0 Min. : 4.0 Min. : 4.0 Min. : 8 Min. : 4.260
## 1st Qu.: 6.5 1st Qu.: 6.5 1st Qu.: 6.5 1st Qu.: 8 1st Qu.: 6.315
## Median : 9.0 Median : 9.0 Median : 9.0 Median : 8 Median : 7.580
## Mean : 9.0 Mean : 9.0 Mean : 9.0 Mean : 9 Mean : 7.501
## 3rd Qu.:11.5 3rd Qu.:11.5 3rd Qu.:11.5 3rd Qu.: 8 3rd Qu.: 8.570
## Max. :14.0 Max. :14.0 Max. :14.0 Max. :19 Max. :10.840
## y2 y3 y4
## Min. :3.100 Min. : 5.39 Min. : 5.250
## 1st Qu.:6.695 1st Qu.: 6.25 1st Qu.: 6.170
## Median :8.140 Median : 7.11 Median : 7.040
## Mean :7.501 Mean : 7.50 Mean : 7.501
## 3rd Qu.:8.950 3rd Qu.: 7.98 3rd Qu.: 8.190
## Max. :9.260 Max. :12.74 Max. :12.500
library("fBasics")
## Loading required package: timeDate
## Loading required package: timeSeries
correlationTest(data$x1,data$y1)
##
## Title:
## Pearson's Correlation Test
##
## Test Results:
## PARAMETER:
## Degrees of Freedom: 9
## SAMPLE ESTIMATES:
## Correlation: 0.8164
## STATISTIC:
## t: 4.2415
## P VALUE:
## Alternative Two-Sided: 0.00217
## Alternative Less: 0.9989
## Alternative Greater: 0.001085
## CONFIDENCE INTERVAL:
## Two-Sided: 0.4244, 0.9507
## Less: -1, 0.9388
## Greater: 0.5113, 1
##
## Description:
## Sun May 17 14:14:23 2020
correlationTest(data$x2,data$y2)
##
## Title:
## Pearson's Correlation Test
##
## Test Results:
## PARAMETER:
## Degrees of Freedom: 9
## SAMPLE ESTIMATES:
## Correlation: 0.8162
## STATISTIC:
## t: 4.2386
## P VALUE:
## Alternative Two-Sided: 0.002179
## Alternative Less: 0.9989
## Alternative Greater: 0.001089
## CONFIDENCE INTERVAL:
## Two-Sided: 0.4239, 0.9506
## Less: -1, 0.9387
## Greater: 0.5109, 1
##
## Description:
## Sun May 17 14:14:23 2020
correlationTest(data$x3,data$y3)
##
## Title:
## Pearson's Correlation Test
##
## Test Results:
## PARAMETER:
## Degrees of Freedom: 9
## SAMPLE ESTIMATES:
## Correlation: 0.8163
## STATISTIC:
## t: 4.2394
## P VALUE:
## Alternative Two-Sided: 0.002176
## Alternative Less: 0.9989
## Alternative Greater: 0.001088
## CONFIDENCE INTERVAL:
## Two-Sided: 0.4241, 0.9507
## Less: -1, 0.9387
## Greater: 0.511, 1
##
## Description:
## Sun May 17 14:14:23 2020
correlationTest(data$x4,data$y4)
##
## Title:
## Pearson's Correlation Test
##
## Test Results:
## PARAMETER:
## Degrees of Freedom: 9
## SAMPLE ESTIMATES:
## Correlation: 0.8165
## STATISTIC:
## t: 4.243
## P VALUE:
## Alternative Two-Sided: 0.002165
## Alternative Less: 0.9989
## Alternative Greater: 0.001082
## CONFIDENCE INTERVAL:
## Two-Sided: 0.4246, 0.9507
## Less: -1, 0.9388
## Greater: 0.5115, 1
##
## Description:
## Sun May 17 14:14:23 2020
#data summary: x1, x2, and x3 are the same. And all 4 pairs of data are correclted, becuase the corretionlation values are: 0.8164;0.8162;0.8163;0.8165.
plot(data$x1,data$y1,main="Scater plot 1")
plot(data$x2,data$y2,main="Scater plot 2")
plot(data$x3,data$y3,main="Scater plot 3")
plot(data$x4,data$y4,main="Scater plot 4")
#data summary: plots indicate the correlation fits between x and y values.
par(mfrow=c(2,2))
plot(data$x1,data$y1,main="Scater plot 1", pch=20)
plot(data$x2,data$y2,main="Scater plot 2",pch=20)
plot(data$x3,data$y3,main="Scater plot 3",pch=20)
plot(data$x4,data$y4,main="Scater plot 4",pch=20)
lm() function.fit1=lm(data$y1~data$x1)
fit1
##
## Call:
## lm(formula = data$y1 ~ data$x1)
##
## Coefficients:
## (Intercept) data$x1
## 3.0001 0.5001
fit2=lm(data$y2~data$x2)
fit2
##
## Call:
## lm(formula = data$y2 ~ data$x2)
##
## Coefficients:
## (Intercept) data$x2
## 3.001 0.500
fit3=lm(data$y3~data$x3)
fit3
##
## Call:
## lm(formula = data$y3 ~ data$x3)
##
## Coefficients:
## (Intercept) data$x3
## 3.0025 0.4997
fit4=lm(data$y4~data$x4)
fit4
##
## Call:
## lm(formula = data$y4 ~ data$x4)
##
## Coefficients:
## (Intercept) data$x4
## 3.0017 0.4999
par(mfrow=c(2,2))
plot(data$x1,data$y1,main="Scater plot 1", pch=20)
abline(fit1)
plot(data$x2,data$y2,main="Scater plot 2",pch=20)
abline(fit2)
plot(data$x3,data$y3,main="Scater plot 3",pch=20)
abline(fit3)
plot(data$x4,data$y4,main="Scater plot 4",pch=20)
abline(fit4)
anova(fit1)
Analysis of Variance Table
Response: data\(y1 Df Sum Sq Mean Sq F value Pr(>F) data\)x1 1 27.510 27.5100 17.99 0.00217 ** Residuals 9 13.763 1.5292
— Signif. codes: 0 ‘’ 0.001 ’’ 0.01 ’’ 0.05 ‘.’ 0.1 ’ ’ 1
anova(fit2)
Analysis of Variance Table
Response: data\(y2 Df Sum Sq Mean Sq F value Pr(>F) data\)x2 1 27.500 27.5000 17.966 0.002179 ** Residuals 9 13.776 1.5307
— Signif. codes: 0 ‘’ 0.001 ’’ 0.01 ’’ 0.05 ‘.’ 0.1 ’ ’ 1
anova(fit3)
Analysis of Variance Table
Response: data\(y3 Df Sum Sq Mean Sq F value Pr(>F) data\)x3 1 27.470 27.4700 17.972 0.002176 ** Residuals 9 13.756 1.5285
— Signif. codes: 0 ‘’ 0.001 ’’ 0.01 ’’ 0.05 ‘.’ 0.1 ’ ’ 1
anova(fit4)
Analysis of Variance Table
Response: data\(y4 Df Sum Sq Mean Sq F value Pr(>F) data\)x4 1 27.490 27.4900 18.003 0.002165 ** Residuals 9 13.742 1.5269
— Signif. codes: 0 ‘’ 0.001 ’’ 0.01 ’’ 0.05 ‘.’ 0.1 ’ ’ 1
# Anscombe's Quartet points out the value of data visualization importance. from the statistics analysis reasults, we can see the values are very close to each other in different modles. However, when we plot out the data, and trough the data visualtion, we can see the values distrubition and correclations are totally different between the 4 models. So we can say, the summary data from statistics may not fully illustrate the corrections from raw data in the data analysis, and that is the reason why we need to visualize the data to do data analysis, which is in somehow strightfoward.