Using the “cars” dataset in R, build a linear model for stopping distance as a function of speed and replicate the analysis of your textbook chapter 3 (visualization, quality evaluation of the model, and residual analysis.)
library(tidyverse)
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## x dplyr::filter() masks stats::filter()
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head(cars)
## speed dist
## 1 4 2
## 2 4 10
## 3 7 4
## 4 7 22
## 5 8 16
## 6 9 10
summary(cars)
## speed dist
## Min. : 4.0 Min. : 2.00
## 1st Qu.:12.0 1st Qu.: 26.00
## Median :15.0 Median : 36.00
## Mean :15.4 Mean : 42.98
## 3rd Qu.:19.0 3rd Qu.: 56.00
## Max. :25.0 Max. :120.00
visualization
plot(cars[,"speed"],cars[,"dist"], xlab="Speed", ylab="Distance")

cars_lm <- lm(cars$dist ~ cars$speed)
plot(cars$speed, cars$dist, main = "Comparsion between speed and distance of cars", xlab = "Speed", ylab="Distance")
abline(cars_lm)

Quality Evaluation of the Model
cars_lm <- lm(cars$dist ~ cars$speed)
cars_lm
##
## Call:
## lm(formula = cars$dist ~ cars$speed)
##
## Coefficients:
## (Intercept) cars$speed
## -17.579 3.932
In this case, the y-intercept is a0 = -17.579 and the slope is a1 = 3.932.
Thus, the final regression model is: Distance = -17.579 + 3.932 x Speed
summary(cars_lm)
##
## Call:
## lm(formula = cars$dist ~ cars$speed)
##
## Residuals:
## Min 1Q Median 3Q Max
## -29.069 -9.525 -2.272 9.215 43.201
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) -17.5791 6.7584 -2.601 0.0123 *
## cars$speed 3.9324 0.4155 9.464 1.49e-12 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 15.38 on 48 degrees of freedom
## Multiple R-squared: 0.6511, Adjusted R-squared: 0.6438
## F-statistic: 89.57 on 1 and 48 DF, p-value: 1.49e-12
Residual Analysis
plot(fitted(cars_lm),resid(cars_lm))

qqnorm(resid(cars_lm))
qqline(resid(cars_lm))

Q-Q plot are not uniformly scattered and have deviation at lower and quantiles. The residual Analysis does not show randomly.