54 R, 9 W, and 75 B marbles. Select marble manually. P(R or B)? \(P(A \cup B)=P(A)+P(B)-P(A \cap B)\)
print(round((54+75-0)/(54+9+75),4)) #P(AB)=0, special rule of addition
## [1] 0.9348
A ball machine has 19 G balls, 20 R balls, 24 B balls, 17 Y balls. Random. P(R)?
print(round(20/(19+20+24+17),4)) #marginal probability
## [1] 0.25
R&D gathered data from N=1399 customers (see Table), \(P(M^C \cap Parents^C)\)
| M | F | |
|---|---|---|
| Apt | 81 | 228 |
| Dorm | 116 | 79 |
| Parents | 215 | 252 |
| Sor/Frat House | 130 | 97 |
| Other | 129 | 72 |
round((sum(p3[,])-p3[3,1])/sum(p3[,]),4) #Subtract intersection of 2, which is 215/1399
## [1] 0.8463
Determine if the following events are independent.Going to the gym. Losing weight.
While not linear, there is likely a relationship of some sort. Not independent.
Wrap = 3 V, 3 C, 1 T with all elements different. Possible = 8V, 7C, 3T. How many wraps possible? t
choose(8,3)*choose(7,3)*choose(3,1) #order does not matter
## [1] 5880
Jeff runs out of gas on the way to work. Liz watches the evening news. Independent?
Probably independent until we find out that Jeff is going to work to avoid his wife Liz.
8 cabinet spots. 14 candidates. Rank matters. How many ways?
comma(choose(14,8)*factorial(8),0) #permutation
## [1] NA
9R, 4O, 9G jellies. P(R=0, O=1, G=3)
round(choose(9,0)*choose(4,1)*choose(9,3)/choose(22,4),4) #multivariate hypergeometric
## [1] 0.0459
Evaluate the following expression: \(\frac{11!}{/7!}\)
choose(11,4)*factorial(4) #P(11,4)
## [1] 7920
Describe the complement of the given event. 67% of subscribers to a fitness magazine are over the age of 34.
The 33% of subscribers of a fitness magazine who are not over the age of 34
Exactly 3 out of 4 heads: win $97. else: lose $30. Find \(E(X_1)\) and \(E(X_{559})\)
c(dbinom(3,4,.5)*97-30*(1-dbinom(3,4,.5)), 559*(dbinom(3,4,.5)*97-30*(1-dbinom(3,4,.5))))
## [1] 1.75 978.25
Flip coin 9 x. <=4 tails = win $23. Else:- $26. Find \(E(X_1)\) and \(E(X_{994})\)
c(pbinom(4,9,.5)*23-26*(1-pbinom(4,9,.5)), 994*(pbinom(4,9,.5)*23-26*(1-pbinom(4,9,.5))))
## [1] -1.5 -1491.0
The sensitivity and specificity of the polygraph has been a subject of study and debate for years. A 2001 study of the use of polygraph for screening purposes suggested that the probability of detecting a liar was .59 (sensitivity) and that the probability of detecting a “truth teller” was .90 (specificity). We estimate that about 20% of individuals selected for the screening polygraph will lie. \(P(A|B)=\frac{P(B|A)P(A)}{P(B)}\))$, A==Liar, B==Positive, AB=Liar and Positive. P(A|B)?
.59*.20/(.59*.20+.1*.8)
## [1] 0.5959596
P(Not Liar | -). \(P(A^c|B^c)=\frac{P(B^c|A^c)P(A^c)}{P(B^c)}\))$
.9*.8/(.9*.8+.41*.2)
## [1] 0.8977556
P(Liar or +) = \(P(A \cup B)=P(A)+P(B)-P(A \cap B)\)
.2 +.591*.2+.1*.8-.5959596*.2
## [1] 0.2790081