A symphony orchestra has in its repertoire 30 Haydn symphonies, 15 modern works, and 9 Beethoven symphonies. Its program always consists of a Haydn symphony followed by a modern work, and then a Beethoven symphony.
# Setting global varibles
h <- 30
m <- 15
b <- 9
This is a counting problem where \(({ n }_{ 1 })*({ n }_{ 2 })*.....({ n }_{ n })\). In this case it is \((Haydn)*(Modern)*(Beethoven)\)
(a<- h*m*b)
## [1] 4050
With three types of music, the order can be in 6 different ways:
\[Set 1: Haydn, Modern, Beethoven\] \[Set 2: Haydn, Beethoven, Modern\] \[Set 3: Beethoven, Modern, Haydn\] \[Set 4: Beethoven, Haydn, Modern\] \[Set 5: Modern, Beethoven, Haydn\] \[Set 6: Modern, Haydn, Beethoven\]
Looking at how many different programs could happen (adding the repertoire numbers), we can take this 6 “sets” and multiply it to the 4,050 different programs already identified.
(Qb<- 6*a)
## [1] 24300
piece from the same category can be played and they can be played in any order?
We are really looking at how many three-piece sets of the 54 pieces we can create when order and category does not factor. This is equal to: \[{ _{ 54 }{ P }_{ 3 } }=({ 54 }_{ 3 })=\frac { 54! }{ (54-3)! }\]
n<- h+m+b
(c<- factorial(n)/factorial(n-3))
## [1] 148824