We have 52 cards choose 6. There are 13 heart cards to choose 6.
P(all 6 cards are hearts) = \(\dfrac {13 \choose 6} {52 \choose 6}\) = \(\dfrac {1716} {20358520}\) = 0.000084
We have 52 cards choose 6. There are 4 aces cards to choose 3, 4 kings to choose 2 and 4 queens to choose 1.
P(three aces, two kings, and one queen) = \(\dfrac {{4 \choose 3} \times {4 \choose 2} \times {4 \choose 1}} {52 \choose 6}\) = (4 x 6 x 4) / 20358520 = 0.0000047
There are 4 suites to choose 2, 13 cards in one suit to choose 3 and 13 cards in another suit to choose 3.
P(three cards of one suit and three of another suit) = \({4 \choose 2} \times \dfrac {{13 \choose 3} \times {13 \choose 3}} {52 \choose 6}\) = 6 x (286 x 286 / 20358520) = 0.0241