Many college courses conclude by giving students the opportunity to evaluate the course and the instructor anonymously. However, the use of these student evaluations as an indicator of course quality and teaching effectiveness is often criticized because these measures may reflect the influence of non-teaching related characteristics, such as the physical appearance of the instructor. The article titled, “Beauty in the classroom: instructors’ pulchritude and putative pedagogical productivity” (Hamermesh and Parker, 2005) found that instructors who are viewed to be better looking receive higher instructional ratings. (Daniel S. Hamermesh, Amy Parker, Beauty in the classroom: instructors pulchritude and putative pedagogical productivity, Economics of Education Review, Volume 24, Issue 4, August 2005, Pages 369-376, ISSN 0272-7757, 10.1016/j.econedurev.2004.07.013. http://www.sciencedirect.com/science/article/pii/S0272775704001165.)
In this lab we will analyze the data from this study in order to learn what goes into a positive professor evaluation.
The data were gathered from end of semester student evaluations for a large sample of professors from the University of Texas at Austin. In addition, six students rated the professors’ physical appearance. (This is aslightly modified version of the original data set that was released as part of the replication data for Data Analysis Using Regression and Multilevel/Hierarchical Models (Gelman and Hill, 2007).) The result is a data frame where each row contains a different course and columns represent variables about the courses and professors.
download.file("http://www.openintro.org/stat/data/evals.RData", destfile ="evals.RData")
load("evals.RData")
variable | description |
---|---|
score |
average professor evaluation score: (1) very unsatisfactory - (5) excellent. |
rank |
rank of professor: teaching, tenure track, tenured. |
ethnicity |
ethnicity of professor: not minority, minority. |
gender |
gender of professor: female, male. |
language |
language of school where professor received education: english or non-english. |
age |
age of professor. |
cls_perc_eval |
percent of students in class who completed evaluation. |
cls_did_eval |
number of students in class who completed evaluation. |
cls_students |
total number of students in class. |
cls_level |
class level: lower, upper. |
cls_profs |
number of professors teaching sections in course in sample: single, multiple. |
cls_credits |
number of credits of class: one credit (lab, PE, etc.), multi credit. |
bty_f1lower |
beauty rating of professor from lower level female: (1) lowest - (10) highest. |
bty_f1upper |
beauty rating of professor from upper level female: (1) lowest - (10) highest. |
bty_f2upper |
beauty rating of professor from second upper level female: (1) lowest - (10) highest. |
bty_m1lower |
beauty rating of professor from lower level male: (1) lowest - (10) highest. |
bty_m1upper |
beauty rating of professor from upper level male: (1) lowest - (10) highest. |
bty_m2upper |
beauty rating of professor from second upper level male: (1) lowest - (10) highest. |
bty_avg |
average beauty rating of professor. |
pic_outfit |
outfit of professor in picture: not formal, formal. |
pic_color |
color of professor’s picture: color, black & white. |
1. Is this an observational study or an experiment? The original research question posed in the paper is whether beauty leads directly to the differences in course evaluations. Given the study design, is it possible to answer this question as it is phrased? If not, rephrase the question.
Answer:
1. This is an observational study.
2. It is not possible to answer this question as it is phrased.
3. The question could bve rephrased as ‘whether beauty is correlated with
the differences in course evaluations.’
2. Describe the distribution of score
. Is the distribution skewed? What does that tell you about how students rate courses? Is this what you expected to see? Why, or why not?
Answer:
1. The data `score` has a left skewed unimodal distribution.
2. As this kind of evaluation is conducted at the end of every semester as a quality assessment of the program. The shool would adjust the program accroding to the assessment. We would expected a left skewed distribution of score because it reflects the result of the shool's quality control on the program.
3. Excluding score
, select two other variables and describe their relationship using an appropriate visualization (scatterplot, side-by-side boxplots, or mosaic plot).
Answer:
1. `age` and `bty-avg` are used for comparison.
2. These two variables are negatively linear correlated.
The fundamental phenomenon suggested by the study is that better looking teachers are evaluated more favorably. Let’s create a scatterplot to see if this appears to be the case:
Before we draw conclusions about the trend, compare the number of observations in the data frame with the approximate number of points on the scatterplot. Is anything awry?
4. Replot the scatterplot, but this time use the function jitter()
on the \(y\)- or the \(x\)-coordinate. (Use ?jitter
to learn more.) What was misleading about the initial scatterplot?
Answer:
1. There are overlapped data points in the initial scatterplot which can not be shown as all overlapped points are displayed like a single point.
5. Let’s see if the apparent trend in the plot is something more than natural variation. Fit a linear model called m_bty
to predict average professor score by average beauty rating and add the line to your plot using abline(m_bty)
. Write out the equation for the linear model and interpret the slope. Is average beauty score a statistically significant predictor? Does it appear to be a practically significant predictor?
Answer:
1. Equation: y = 0.06664 * x + 3.88034
2. The slop 0.06664 means for 1 unit increase / decrease of the beauty score, the overall score rating is increased / decreased to change by 0.06664.
3. The `bty_avg` has a p-value 5.08e-05 < 0.05, therefore it is a statistically significant predictor.
4. The correlation coefficient 0.1871424 is very low, which means the relationship of the two variables are not strong. Therefore `bty-avg` is not a practically significant predictor.
##
## Call:
## lm(formula = score ~ bty_avg, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.9246 -0.3690 0.1420 0.3977 0.9309
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 3.88034 0.07614 50.96 < 2e-16 ***
## bty_avg 0.06664 0.01629 4.09 5.08e-05 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.5348 on 461 degrees of freedom
## Multiple R-squared: 0.03502, Adjusted R-squared: 0.03293
## F-statistic: 16.73 on 1 and 461 DF, p-value: 5.083e-05
## [1] 0.1871424
6. Use residual plots to evaluate whether the conditions of least squares regression are reasonable. Provide plots and comments for each one (see the Simple Regression Lab for a reminder of how to make these).
Answer:
1. Linearty:
The residuals dispersed most at the upper left of the plot. It doesn't seem to be randomly dispersed.
2. Nearly normal residuals
The histogram shows a unimodal and left skewed distribution. The distribution of resudials are not normal.
3. Constant variability
The majority of residuals are distributed between -1 and 1. The constant variability apprears to be met.
Based on the three observation above, the linear model is not reliable.
plot(m_bty$residuals ~ jitter(evals$bty_avg),
xlab = "bty_avg",
ylab = "residual",
main = "residual vs bty_avg")
abline(h = 0, col="red", lty = 3)
The data set contains several variables on the beauty score of the professor: individual ratings from each of the six students who were asked to score the physical appearance of the professors and the average of these six scores. Let’s take a look at the relationship between one of these scores and the average beauty score.
As expected the relationship is quite strong - after all, the average score is calculated using the individual scores. We can actually take a look at the relationships between all beauty variables (columns 13 through 19) using the following command:
These variables are collinear (correlated), and adding more than one of these variables to the model would not add much value to the model. In this application and with these highly-correlated predictors, it is reasonable to use the average beauty score as the single representative of these variables.
In order to see if beauty is still a significant predictor of professor score after we’ve accounted for the gender of the professor, we can add the gender term into the model.
##
## Call:
## lm(formula = score ~ bty_avg + gender, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.8305 -0.3625 0.1055 0.4213 0.9314
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 3.74734 0.08466 44.266 < 2e-16 ***
## bty_avg 0.07416 0.01625 4.563 6.48e-06 ***
## gendermale 0.17239 0.05022 3.433 0.000652 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.5287 on 460 degrees of freedom
## Multiple R-squared: 0.05912, Adjusted R-squared: 0.05503
## F-statistic: 14.45 on 2 and 460 DF, p-value: 8.177e-07
7. P-values and parameter estimates should only be trusted if the conditions for the regression are reasonable. Verify that the conditions for this model are reasonable using diagnostic plots.
Answer:
1. Linearty:
The residuals dispersed most at the upper left of the plot. It doesn't seem to be fully randomly dispersed, but better than the dispersement in question 6.
2. Nearly normal residuals
The histogram shows a unimodal and left skewed distribution. The distribution of resudials are not normal.
3. Constant variability
The majority of residuals are distributed between -1 and 1. The constant variability apprears to be met.
Based on the three observation above, the linear model is not reliable.
8. Is bty_avg
still a significant predictor of score
? Has the addition of gender
to the model changed the parameter estimate for bty_avg
?
Answer:
1. The p-value for `bty-avg` changed from 5.08e-05 to 6.48e-06, still statistically significant for prediction.
2. The correlation coeffiection of `bty_avg` incresed from 0.06664 to 0.074155, which still shows a week correlation.
Note that the estimate for gender
is now called gendermale
. You’ll see this name change whenever you introduce a categorical variable. The reason is that R recodes gender
from having the values of female
and male
to being an indicator variable called gendermale
that takes a value of \(0\) for females and a value of \(1\) for males. (Such variables are often referred to as “dummy” variables.)
As a result, for females, the parameter estimate is multiplied by zero, leaving the intercept and slope form familiar from simple regression.
\[ \begin{aligned} \widehat{score} &= \hat{\beta}_0 + \hat{\beta}_1 \times bty\_avg + \hat{\beta}_2 \times (0) \\ &= \hat{\beta}_0 + \hat{\beta}_1 \times bty\_avg\end{aligned} \]
We can plot this line and the line corresponding to males with the following custom function.
9. What is the equation of the line corresponding to males? (Hint: For males, the parameter estimate is multiplied by 1.) For two professors who received the same beauty rating, which gender tends to have the higher course evaluation score?
Answer:
The decision to call the indicator variable gendermale
instead ofgenderfemale
has no deeper meaning. R simply codes the category that comes first alphabetically as a \(0\). (You can change the reference level of a categorical variable, which is the level that is coded as a 0, using therelevel
function. Use ?relevel
to learn more.)
10. Create a new model called m_bty_rank
with gender
removed and rank
added in. How does R appear to handle categorical variables that have more than two levels? Note that the rank variable has three levels: teaching
, tenure track
, tenured
.
Answer:
1. For a categorical variable that have N levels, R created N-1 dummy variables for the categorical variable. The level which comes first alphabetically in the categorical variable is treated as a base level by having a coefficient = 0, and no dummy variable is created for it.
2. In this question, two dummy variables `tenure track` and `tenured` are created in the model. The level `teaching` which comes first alphabetivally in the categorical variable `rank` is treated as a base level.
##
## Call:
## lm(formula = evals$score ~ evals$bty_avg + evals$rank)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.8713 -0.3642 0.1489 0.4103 0.9525
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 3.98155 0.09078 43.860 < 2e-16 ***
## evals$bty_avg 0.06783 0.01655 4.098 4.92e-05 ***
## evals$ranktenure track -0.16070 0.07395 -2.173 0.0303 *
## evals$ranktenured -0.12623 0.06266 -2.014 0.0445 *
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.5328 on 459 degrees of freedom
## Multiple R-squared: 0.04652, Adjusted R-squared: 0.04029
## F-statistic: 7.465 on 3 and 459 DF, p-value: 6.88e-05
The interpretation of the coefficients in multiple regression is slightly different from that of simple regression. The estimate for bty_avg
reflects how much higher a group of professors is expected to score if they have a beauty rating that is one point higher while holding all other variables constant. In this case, that translates into considering only professors of the same rank with bty_avg
scores that are one point apart.
We will start with a full model that predicts professor score based on rank, ethnicity, gender, language of the university where they got their degree, age, proportion of students that filled out evaluations, class size, course level, number of professors, number of credits, average beauty rating, outfit, and picture color.
11. Which variable would you expect to have the highest p-value in this model? Why? Hint: Think about which variable would you expect to not have any association with the professor score.
Answer:
1. Before runing any statistics, I would expect `cls_profs` would have the least impact on professor score.
Let’s run the model…
m_full <- lm(score ~ rank + ethnicity + gender + language + age + cls_perc_eval
+ cls_students + cls_level + cls_profs + cls_credits + bty_avg
+ pic_outfit + pic_color, data = evals)
summary(m_full)
##
## Call:
## lm(formula = score ~ rank + ethnicity + gender + language + age +
## cls_perc_eval + cls_students + cls_level + cls_profs + cls_credits +
## bty_avg + pic_outfit + pic_color, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.77397 -0.32432 0.09067 0.35183 0.95036
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 4.0952141 0.2905277 14.096 < 2e-16 ***
## ranktenure track -0.1475932 0.0820671 -1.798 0.07278 .
## ranktenured -0.0973378 0.0663296 -1.467 0.14295
## ethnicitynot minority 0.1234929 0.0786273 1.571 0.11698
## gendermale 0.2109481 0.0518230 4.071 5.54e-05 ***
## languagenon-english -0.2298112 0.1113754 -2.063 0.03965 *
## age -0.0090072 0.0031359 -2.872 0.00427 **
## cls_perc_eval 0.0053272 0.0015393 3.461 0.00059 ***
## cls_students 0.0004546 0.0003774 1.205 0.22896
## cls_levelupper 0.0605140 0.0575617 1.051 0.29369
## cls_profssingle -0.0146619 0.0519885 -0.282 0.77806
## cls_creditsone credit 0.5020432 0.1159388 4.330 1.84e-05 ***
## bty_avg 0.0400333 0.0175064 2.287 0.02267 *
## pic_outfitnot formal -0.1126817 0.0738800 -1.525 0.12792
## pic_colorcolor -0.2172630 0.0715021 -3.039 0.00252 **
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.498 on 448 degrees of freedom
## Multiple R-squared: 0.1871, Adjusted R-squared: 0.1617
## F-statistic: 7.366 on 14 and 448 DF, p-value: 6.552e-14
12. Check your suspicions from the previous exercise. Include the model output in your response.
Answer:
1. the coefficient `cls_profssingle` has the highest p-value 0.77806.
13. Interpret the coefficient associated with the ethnicity variable.
Answer:
1. The value of the coefficient `ethnicitynot minority` is 0.1234929 means a professers who re not ethnicity minorities have overall score 0.1234929 higher than those who are ethnicity minorities, keeping all other variable constant.
14. Drop the variable with the highest p-value and re-fit the model. Did the coefficients and significance of the other explanatory variables change? (One of the things that makes multiple regression interesting is that coefficient estimates depend on the other variables that are included in the model.) If not, what does this say about whether or not the dropped variable was collinear with the other explanatory variables?
Answer:
1. The coefficients and significances of other variables are slightly changed.
2. This means the collinearty of the dropped variable to the other variables is not significant.
m_drop_1 <- lm(score ~ rank + ethnicity + gender + language + age + cls_perc_eval
+ cls_students + cls_level + cls_credits + bty_avg
+ pic_outfit + pic_color, data = evals)
summary(m_drop_1)
##
## Call:
## lm(formula = score ~ rank + ethnicity + gender + language + age +
## cls_perc_eval + cls_students + cls_level + cls_credits +
## bty_avg + pic_outfit + pic_color, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.7836 -0.3257 0.0859 0.3513 0.9551
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 4.0872523 0.2888562 14.150 < 2e-16 ***
## ranktenure track -0.1476746 0.0819824 -1.801 0.072327 .
## ranktenured -0.0973829 0.0662614 -1.470 0.142349
## ethnicitynot minority 0.1274458 0.0772887 1.649 0.099856 .
## gendermale 0.2101231 0.0516873 4.065 5.66e-05 ***
## languagenon-english -0.2282894 0.1111305 -2.054 0.040530 *
## age -0.0089992 0.0031326 -2.873 0.004262 **
## cls_perc_eval 0.0052888 0.0015317 3.453 0.000607 ***
## cls_students 0.0004687 0.0003737 1.254 0.210384
## cls_levelupper 0.0606374 0.0575010 1.055 0.292200
## cls_creditsone credit 0.5061196 0.1149163 4.404 1.33e-05 ***
## bty_avg 0.0398629 0.0174780 2.281 0.023032 *
## pic_outfitnot formal -0.1083227 0.0721711 -1.501 0.134080
## pic_colorcolor -0.2190527 0.0711469 -3.079 0.002205 **
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.4974 on 449 degrees of freedom
## Multiple R-squared: 0.187, Adjusted R-squared: 0.1634
## F-statistic: 7.943 on 13 and 449 DF, p-value: 2.336e-14
15. Using backward-selection and p-value as the selection criterion, determine the best model. You do not need to show all steps in your answer, just the output for the final model. Also, write out the linear model for predicting score based on the final model you settle on.
Answer:
1. Use `step` function and remove the coefficients that with p-value > 0.05, we get the final model with variables `ethnicity`, `gender`, `language`, `age`,`cls_prec_eval`,`cls_credits`,`bty_avg`,`pic_color`
## Start: AIC=-630.9
## score ~ rank + ethnicity + gender + language + age + cls_perc_eval +
## cls_students + cls_level + cls_profs + cls_credits + bty_avg +
## pic_outfit + pic_color
##
## Df Sum of Sq RSS AIC
## - cls_profs 1 0.0197 111.11 -632.82
## - cls_level 1 0.2740 111.36 -631.76
## - cls_students 1 0.3599 111.44 -631.40
## - rank 2 0.8930 111.98 -631.19
## <none> 111.08 -630.90
## - pic_outfit 1 0.5768 111.66 -630.50
## - ethnicity 1 0.6117 111.70 -630.36
## - language 1 1.0557 112.14 -628.52
## - bty_avg 1 1.2967 112.38 -627.53
## - age 1 2.0456 113.13 -624.45
## - pic_color 1 2.2893 113.37 -623.46
## - cls_perc_eval 1 2.9698 114.06 -620.69
## - gender 1 4.1085 115.19 -616.09
## - cls_credits 1 4.6495 115.73 -613.92
##
## Step: AIC=-632.82
## score ~ rank + ethnicity + gender + language + age + cls_perc_eval +
## cls_students + cls_level + cls_credits + bty_avg + pic_outfit +
## pic_color
##
## Df Sum of Sq RSS AIC
## - cls_level 1 0.2752 111.38 -633.67
## - cls_students 1 0.3893 111.49 -633.20
## - rank 2 0.8939 112.00 -633.11
## <none> 111.11 -632.82
## - pic_outfit 1 0.5574 111.66 -632.50
## - ethnicity 1 0.6728 111.78 -632.02
## - language 1 1.0442 112.15 -630.49
## - bty_avg 1 1.2872 112.39 -629.49
## - age 1 2.0422 113.15 -626.39
## - pic_color 1 2.3457 113.45 -625.15
## - cls_perc_eval 1 2.9502 114.06 -622.69
## - gender 1 4.0895 115.19 -618.08
## - cls_credits 1 4.7999 115.90 -615.24
##
## Step: AIC=-633.67
## score ~ rank + ethnicity + gender + language + age + cls_perc_eval +
## cls_students + cls_credits + bty_avg + pic_outfit + pic_color
##
## Df Sum of Sq RSS AIC
## - cls_students 1 0.2459 111.63 -634.65
## - rank 2 0.8140 112.19 -634.30
## <none> 111.38 -633.67
## - pic_outfit 1 0.6618 112.04 -632.93
## - ethnicity 1 0.8698 112.25 -632.07
## - language 1 0.9015 112.28 -631.94
## - bty_avg 1 1.3694 112.75 -630.02
## - age 1 1.9342 113.31 -627.70
## - pic_color 1 2.0777 113.46 -627.12
## - cls_perc_eval 1 3.0290 114.41 -623.25
## - gender 1 3.8989 115.28 -619.74
## - cls_credits 1 4.5296 115.91 -617.22
##
## Step: AIC=-634.65
## score ~ rank + ethnicity + gender + language + age + cls_perc_eval +
## cls_credits + bty_avg + pic_outfit + pic_color
##
## Df Sum of Sq RSS AIC
## - rank 2 0.7892 112.42 -635.39
## <none> 111.63 -634.65
## - ethnicity 1 0.8832 112.51 -633.00
## - pic_outfit 1 0.9700 112.60 -632.65
## - language 1 1.0338 112.66 -632.38
## - bty_avg 1 1.5783 113.20 -630.15
## - pic_color 1 1.9477 113.57 -628.64
## - age 1 2.1163 113.74 -627.96
## - cls_perc_eval 1 2.7922 114.42 -625.21
## - gender 1 4.0945 115.72 -619.97
## - cls_credits 1 4.5163 116.14 -618.29
##
## Step: AIC=-635.39
## score ~ ethnicity + gender + language + age + cls_perc_eval +
## cls_credits + bty_avg + pic_outfit + pic_color
##
## Df Sum of Sq RSS AIC
## <none> 112.42 -635.39
## - pic_outfit 1 0.7141 113.13 -634.46
## - ethnicity 1 1.1790 113.59 -632.56
## - language 1 1.3403 113.75 -631.90
## - age 1 1.6847 114.10 -630.50
## - pic_color 1 1.7841 114.20 -630.10
## - bty_avg 1 1.8553 114.27 -629.81
## - cls_perc_eval 1 2.9147 115.33 -625.54
## - gender 1 4.0577 116.47 -620.97
## - cls_credits 1 6.1208 118.54 -612.84
m_step_final <- lm(formula = score ~ ethnicity + gender + language + age +
cls_perc_eval + cls_credits + bty_avg + pic_color, data = evals)
summary(m_step_final)
##
## Call:
## lm(formula = score ~ ethnicity + gender + language + age + cls_perc_eval +
## cls_credits + bty_avg + pic_color, data = evals)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.85320 -0.32394 0.09984 0.37930 0.93610
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 3.771922 0.232053 16.255 < 2e-16 ***
## ethnicitynot minority 0.167872 0.075275 2.230 0.02623 *
## gendermale 0.207112 0.050135 4.131 4.30e-05 ***
## languagenon-english -0.206178 0.103639 -1.989 0.04726 *
## age -0.006046 0.002612 -2.315 0.02108 *
## cls_perc_eval 0.004656 0.001435 3.244 0.00127 **
## cls_creditsone credit 0.505306 0.104119 4.853 1.67e-06 ***
## bty_avg 0.051069 0.016934 3.016 0.00271 **
## pic_colorcolor -0.190579 0.067351 -2.830 0.00487 **
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.4992 on 454 degrees of freedom
## Multiple R-squared: 0.1722, Adjusted R-squared: 0.1576
## F-statistic: 11.8 on 8 and 454 DF, p-value: 2.58e-15
16. Verify that the conditions for this model are reasonable using diagnostic plots.
Answer:
1. Linearty:
For the quantitative variables `age`, `cls_perc_eval`, `bty_avg`: The residuals are most likely to be randomly dispersed, no obvious shapes or patterns are found.
2. Nearly normal residuals
The histogram of the residuals shows a unimodal and left skewed distribution. The qq plot shows the residuals are mostly line along on the normal line.The normal residual condiction is somewhat met.
3. Constant variability
The majority of residuals are distributed between -1 and 1. The constant variability apprears to be met.
Based on the three observation above, the linear model is reliable.
par(mfrow=c(1,3))
plot(jitter(evals$age), resid(m_step_final))
abline(h=0, col="deeppink")
plot(jitter(evals$cls_perc_eval), resid(m_step_final))
abline(h=0, col="deeppink")
plot(jitter(evals$bty_avg), resid(m_step_final))
abline(h=0, col="deeppink")
par(mfrow=c(2,3))
boxplot(m_step_final$residuals~evals$ethnicity)
boxplot(m_step_final$residuals~evals$gender)
boxplot(m_step_final$residuals~evals$language)
boxplot(m_step_final$residuals~evals$cls_credits)
boxplot(m_step_final$residuals~evals$pic_color)
par(mfrow=c(1,1))
17. The original paper describes how these data were gathered by taking a sample of professors from the University of Texas at Austin and including all courses that they have taught. Considering that each row represents a course, could this new information have an impact on any of the conditions of linear regression?
Answer:
1. This condition will break the assumption that all sample cases are randomly collected and are independent of each other.
18. Based on your final model, describe the characteristics of a professor and course at University of Texas at Austin that would be associated with a high evaluation score.
Answer:
1. The final model contains 8 variables including `ethnicity`, `gender`, `language`, `age`,`cls_prec_eval`,`cls_credits`,`bty_avg`,`pic_color`. According to the model, a yong male professor who is not minor ethnicity, graduated from a English-speaking universitiy, with a black and white profile picture, high average beauty score, and high percentage of students who completed the evaluation ususally has higher overall score.
19. Would you be comfortable generalizing your conclusions to apply to professors generally (at any university)? Why or why not?
Answer:
1. The data is collected from single university which can not represent all uniersities, therefore the model that is built on this data can not be applied to other universities.