Exercise 1 (ex.11)

The price of one share of stock in the Pilsdorff Beer Company is given by Yn on the nth day of the year. Finn observes that the differences Xn = Yn+1 − Yn appear to be independent random variables with a common distribution having mean μ = 0 and variance σ2 = 1/4. If Y1 = 100, estimate the probability that Y365 is

  1. ≥ 100

μ = 0

σ2 = 0.25

n = 365

pnorm(100, mean = 100, sd = sqrt(0.25*364), lower.tail = F)
## [1] 0.5
  1. ≥ 110
pnorm(110, mean = 100, sd = sqrt(0.25*364), lower.tail = F)
## [1] 0.1472537
  1. ≥ 120
pnorm(120, mean = 100, sd = sqrt(0.25*364), lower.tail = F)
## [1] 0.01801584

Exercise 2

Every consecutive derivative of the MGF gives a different moment. Each moment is equal to the expected value of X raised to the power of the number of the moment.

By taking the first derivative (n = 1) of the MGF and setting t equal to 0, we find the expected value or mean of random variable X. The second derivative (n = 2) then gives us the expected value of X2, which can be used to find variance with the following formula:

Var [X] = E[X^2] - (E[X2])^2

https://study.com/academy/lesson/moment-generating-functions-definition-equations-examples.html

Calculate the expected value and variance of the binomial distribution using the moment generating function.

g′(0) = n(pe^0 + q)^(n−1) pe^ = np

g″(0) = n(n−1)p^2+np

μ=np

σ^2 = g″(0) − g′(0)^2 = n(n−1)p^2 + np − (np)^2 = np(1−p)

Exercise 3

Calculate the expected value and variance of the exponential distribution using the moment generating function.

gn(0) = n!/λ^n

g′(0) = 1/λ

g″(0) = 2/λ^2

μ = 1/λ

σ2 = 2/λ^2 − (1/λ)^2 = 1/λ^2