Both criteria will use \(E_i, i \in \mathbb{N^+}\) as a set of events
Pairwise independence is present where the following is satisfied:
\[ P(E_i \cap E_j) = P(E_i) \cdot P(E_j) \\ where \ j \not = i, \ j \in \mathbb{N^+} \]
Mutual independence is present where the following is satisfied:
\[ P(\bigcap_{i \in \mathbb{N^+}} E_i) = \prod_{i \in \mathbb{N^+}}P(E_i) \]