Chapter R: Respresentations
Question C10, Page 512
To find a solution for:
\[\rho_B(y)\]
it is necessary to find scalars:
\[a_1, a_2, a_3\]
such that:
\[y = a_1u_1 + a_2u_2 + a_3u_3\]
We get the following system of equations:
2a + 1b + 3c = 11
-2a + 3b + 5c = 5
2a + 1b + 2c = 8
We can solve this using matrix row operations and substitution.
## [,1] [,2] [,3] [,4]
## [1,] 2 1 3 11
## [2,] -2 3 5 5
## [3,] 2 1 2 8
First, subtract row 1 from row 3.
## [,1] [,2] [,3] [,4]
## [1,] 2 1 3 11
## [2,] -2 3 5 5
## [3,] 0 0 -1 -3
From this step, we get that -1c = -3. Solving for c, we get c = 3. We can substitute this into the system of equations and create a new matrix:
2a + 1b + 3(3) = 11
-2a + 3b + 5(3) = 5
The equations above become this:
2a + 1b = 2
-2a + 3b = -10
Adding the two equations together, we get:
4b = -8
b = -2
Finally, solving for a, we get:
2a - 2 = 2
2a = 4
a = 2
Therefore, the representation is:
\[\rho_B(y) = \left(\begin{array}{cc} 2\\ -2\\ 3 \end{array}\right)\]: