Exercise 2.4

Exercise 2.6

Sample mean = 6.25 Claimed mean = 5.5

Exercise 2.7

The manager would be able to raise the average by getting rid of any 10 employees that recieve between the minimum and the mean of average days off.

Exercise 2.10

a

2

b

3

c

1

Exercise 2.15

a

The distribution would be right skewed because more people will have 0 to 1 pets than the outliers that will have many pets. The center will be the median. The variability would be IQR.

b

The distribution would be right skewed because people tend to live close to where they work. The center would be the median and variability would be IQR.

c

The distribution would be symmetric. The center would be the mean and variability would be standard deviation

Exercise 2.16

a

The data would be right skewed because 75% of the houses are under a million dollars. The median would show the center. The variability would be IQR.

b

The data would be symmetric. The mean would be the center and the variability would be standard deviation.

c

The data would be right skewed because most people in college students are under 21 so they do not drink. The center would be the median and the variability would be IQR.

d

The data would be symmetric because you will have a couple people like janitors that make little salaries and executives that make much higher salaries than everyone else. The center would be the mean and the variability would be standard deviation.

Exercise 2.17

a

The median is better for a sample size of 42 people. The mean is less accurate because with a sample size that small the outliers will effect the mean heavily. The median will be less affected by large outliers.

b

The IQR will be more accurate because outliers will have less of an effect on the IQR. The standard deviation will be skewed because outliers in the small sample size will greatly effect the data.

Exercise 2.24

The support of taxing the rich and the poor is dependent on what political view people have.