Some define Statistics as the field that focuses on turning information into knowledge. The first step in that process is to summarize and describe the raw information - the data. In this lab, you will gain insight into public health by generating simple graphical and numerical summaries of a data set collected by the Centers for Disease Control and Prevention (CDC). As this is a large data set, along the way you’ll also learn the indispensable skills of data processing and subsetting.
The Behavioral Risk Factor Surveillance System (BRFSS) is an annual telephone survey of 350,000 people in the United States. As its name implies, the BRFSS is designed to identify risk factors in the adult population and report emerging health trends. For example, respondents are asked about their diet and weekly physical activity, their HIV/AIDS status, possible tobacco use, and even their level of healthcare coverage. The BRFSS Web site (http://www.cdc.gov/brfss) contains a complete description of the survey, including the research questions that motivate the study and many interesting results derived from the data.
We will focus on a random sample of 20,000 people from the BRFSS survey conducted in 2000. While there are over 200 variables in this data set, we will work with a small subset.
We begin by loading the data set of 20,000 observations into the R workspace. After launching RStudio, enter the following command.
The data set cdc
that shows up in your workspace is a data matrix, with each row representing a case and each column representing a variable. R calls this data format a data frame, which is a term that will be used throughout the labs.
To view the names of the variables, type the command
## [1] "genhlth" "exerany" "hlthplan" "smoke100" "height" "weight"
## [7] "wtdesire" "age" "gender"
This returns the names genhlth
, exerany
, hlthplan
, smoke100
, height
, weight
, wtdesire
, age
, and gender
. Each one of these variables corresponds to a question that was asked in the survey. For example, for genhlth
, respondents were asked to evaluate their general health, responding either excellent, very good, good, fair or poor. The exerany
variable indicates whether the respondent exercised in the past month (1) or did not (0). Likewise, hlthplan
indicates whether the respondent had some form of health coverage (1) or did not (0). The smoke100
variable indicates whether the respondent had smoked at least 100 cigarettes in her lifetime. The other variables record the respondent’s height
in inches, weight
in pounds as well as their desired weight, wtdesire
, age
in years, and gender
.
We can have a look at the first few entries (rows) of our data with the command
## genhlth exerany hlthplan smoke100 height weight wtdesire age gender
## 1 good 0 1 0 70 175 175 77 m
## 2 good 0 1 1 64 125 115 33 f
## 3 good 1 1 1 60 105 105 49 f
## 4 good 1 1 0 66 132 124 42 f
## 5 very good 0 1 0 61 150 130 55 f
## 6 very good 1 1 0 64 114 114 55 f
and similarly we can look at the last few by typing
## genhlth exerany hlthplan smoke100 height weight wtdesire age
## 19995 good 0 1 1 69 224 224 73
## 19996 good 1 1 0 66 215 140 23
## 19997 excellent 0 1 0 73 200 185 35
## 19998 poor 0 1 0 65 216 150 57
## 19999 good 1 1 0 67 165 165 81
## 20000 good 1 1 1 69 170 165 83
## gender
## 19995 m
## 19996 f
## 19997 m
## 19998 f
## 19999 f
## 20000 m
You could also look at all of the data frame at once by typing its name into the console, but that might be unwise here. We know cdc
has 20,000 rows, so viewing the entire data set would mean flooding your screen. It’s better to take small peeks at the data with head
, tail
or the subsetting techniques that you’ll learn in a moment.
The BRFSS questionnaire is a massive trove of information. A good first step in any analysis is to distill all of that information into a few summary statistics and graphics. As a simple example, the function summary
returns a numerical summary: minimum, first quartile, median, mean, second quartile, and maximum. For weight
this is
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 68.0 140.0 165.0 169.7 190.0 500.0
R also functions like a very fancy calculator. If you wanted to compute the interquartile range for the respondents’ weight, you would look at the output from the summary command above and then enter
## [1] 50
R also has built-in functions to compute summary statistics one by one. For instance, to calculate the mean, median, and variance of weight
, type
## [1] 169.683
## [1] 1606.484
## [1] 165
While it makes sense to describe a quantitative variable like weight
in terms of these statistics, what about categorical data? We would instead consider the sample frequency or relative frequency distribution. The function table
does this for you by counting the number of times each kind of response was given. For example, to see the number of people who have smoked 100 cigarettes in their lifetime, type
##
## 0 1
## 10559 9441
or instead look at the relative frequency distribution by typing
##
## 0 1
## 0.52795 0.47205
Notice how R automatically divides all entries in the table by 20,000 in the command above. This is similar to something we observed in the Introduction to R; when we multiplied or divided a vector with a number, R applied that action across entries in the vectors. As we see above, this also works for tables. Next, we make a bar plot of the entries in the table by putting the table inside the barplot
command.
Notice what we’ve done here! We’ve computed the table of cdc$smoke100
and then immediately applied the graphical function, barplot
. This is an important idea: R commands can be nested. You could also break this into two steps by typing the following:
Here, we’ve made a new object, a table, called smoke
(the contents of which we can see by typing smoke
into the console) and then used it in as the input for barplot
. The special symbol <-
performs an assignment, taking the output of one line of code and saving it into an object in your workspace. This is another important idea that we’ll return to later.
height
and age
, and compute the interquartile range for each. Compute the relative frequency distribution for gender
and exerany
. How many males are in the sample? What proportion of the sample reports being in excellent health?## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 48.00 64.00 67.00 67.18 70.00 93.00
## [1] 6
Ans: IQR = 6 for height
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 18.00 31.00 43.00 45.07 57.00 99.00
## [1] 26
Ans: IQR = 26 for age
##
## m f
## 9569 10431
##
## m f
## 0.47845 0.52155
Ans:
There are 47% male in the study or 9659
##
## 0 1
## 5086 14914
##
## 0 1
## 0.2543 0.7457
Ans:
74% of respondents claim to have exercised or 14914
The table
command can be used to tabulate any number of variables that you provide. For example, to examine which participants have smoked across each gender, we could use the following.
##
## 0 1
## m 4547 5022
## f 6012 4419
Here, we see column labels of 0 and 1. Recall that 1 indicates a respondent has smoked at least 100 cigarettes. The rows refer to gender. To create a mosaic plot of this table, we would enter the following command.
We could have accomplished this in two steps by saving the table in one line and applying mosaicplot
in the next (see the table/barplot example above).
Female smoked less than Men
We mentioned that R stores data in data frames, which you might think of as a type of spreadsheet. Each row is a different observation (a different respondent) and each column is a different variable (the first is genhlth
, the second exerany
and so on). We can see the size of the data frame next to the object name in the workspace or we can type
## [1] 20000 9
which will return the number of rows and columns. Now, if we want to access a subset of the full data frame, we can use row-and-column notation. For example, to see the sixth variable of the 567th respondent, use the format
## [1] 160
which means we want the element of our data set that is in the 567th row (meaning the 567th person or observation) and the 6th column (in this case, weight). We know that weight
is the 6th variable because it is the 6th entry in the list of variable names
## [1] "genhlth" "exerany" "hlthplan" "smoke100" "height" "weight"
## [7] "wtdesire" "age" "gender"
To see the weights for the first 10 respondents we can type
## [1] 175 125 105 132 150 114 194 170 150 180
In this expression, we have asked just for rows in the range 1 through 10. R uses the :
to create a range of values, so 1:10 expands to 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. You can see this by entering
## [1] 1 2 3 4 5 6 7 8 9 10
Finally, if we want all of the data for the first 10 respondents, type
## genhlth exerany hlthplan smoke100 height weight wtdesire age gender
## 1 good 0 1 0 70 175 175 77 m
## 2 good 0 1 1 64 125 115 33 f
## 3 good 1 1 1 60 105 105 49 f
## 4 good 1 1 0 66 132 124 42 f
## 5 very good 0 1 0 61 150 130 55 f
## 6 very good 1 1 0 64 114 114 55 f
## 7 very good 1 1 0 71 194 185 31 m
## 8 very good 0 1 0 67 170 160 45 m
## 9 good 0 1 1 65 150 130 27 f
## 10 good 1 1 0 70 180 170 44 m
By leaving out an index or a range (we didn’t type anything between the comma and the square bracket), we get all the columns. When starting out in R, this is a bit counterintuitive. As a rule, we omit the column number to see all columns in a data frame. Similarly, if we leave out an index or range for the rows, we would access all the observations, not just the 567th, or rows 1 through 10. Try the following to see the weights for all 20,000 respondents fly by on your screen
## [1] 175 125 105 132 150 114
Recall that column 6 represents respondents’ weight, so the command above reported all of the weights in the data set. An alternative method to access the weight data is by referring to the name. Previously, we typed names(cdc)
to see all the variables contained in the cdc data set. We can use any of the variable names to select items in our data set.
## [1] 175 125 105 132 150 114
The dollar-sign tells R to look in data frame cdc
for the column called weight
. Since that’s a single vector, we can subset it with just a single index inside square brackets. We see the weight for the 567th respondent by typing
## [1] 160
Similarly, for just the first 10 respondents
## [1] 175 125 105 132 150 114 194 170 150 180
The command above returns the same result as the cdc[1:10,6]
command. Both row-and-column notation and dollar-sign notation are widely used, which one you choose to use depends on your personal preference.
It’s often useful to extract all individuals (cases) in a data set that have specific characteristics. We accomplish this through conditioning commands. First, consider expressions like
## [1] TRUE FALSE FALSE FALSE FALSE FALSE
or
## [1] TRUE TRUE TRUE TRUE TRUE TRUE
These commands produce a series of TRUE
and FALSE
values. There is one value for each respondent, where TRUE
indicates that the person was male (via the first command) or older than 30 (second command).
Suppose we want to extract just the data for the men in the sample, or just for those over 30. We can use the R function subset
to do that for us. For example, the command
will create a new data set called mdata
that contains only the men from the cdc
data set. In addition to finding it in your workspace alongside its dimensions, you can take a peek at the first several rows as usual
## genhlth exerany hlthplan smoke100 height weight wtdesire age gender
## 1 good 0 1 0 70 175 175 77 m
## 7 very good 1 1 0 71 194 185 31 m
## 8 very good 0 1 0 67 170 160 45 m
## 10 good 1 1 0 70 180 170 44 m
## 11 excellent 1 1 1 69 186 175 46 m
## 12 fair 1 1 1 69 168 148 62 m
This new data set contains all the same variables but just under half the rows. It is also possible to tell R to keep only specific variables, which is a topic we’ll discuss in a future lab. For now, the important thing is that we can carve up the data based on values of one or more variables.
As an aside, you can use several of these conditions together with &
and |
. The &
is read “and” so that
will give you the data for men over the age of 30. The |
character is read “or” so that
will take people who are men or over the age of 30 (why that’s an interesting group is hard to say, but right now the mechanics of this are the important thing). In principle, you may use as many “and” and “or” clauses as you like when forming a subset.
under23_and_smoke
that contains all observations of respondents under the age of 23 that have smoked 100 cigarettes in their lifetime. Write the command you used to create the new object as the answer to this exercise.## genhlth exerany hlthplan smoke100 height weight wtdesire age gender
## 13 excellent 1 0 1 66 185 220 21 m
## 37 very good 1 0 1 70 160 140 18 f
## 96 excellent 1 1 1 74 175 200 22 m
## 180 good 1 1 1 64 190 140 20 f
## 182 very good 1 1 1 62 92 92 21 f
## 240 very good 1 0 1 64 125 115 22 f
With our subsetting tools in hand, we’ll now return to the task of the day: making basic summaries of the BRFSS questionnaire. We’ve already looked at categorical data such as smoke
and gender
so now let’s turn our attention to quantitative data. Two common ways to visualize quantitative data are with box plots and histograms. We can construct a box plot for a single variable with the following command.
You can compare the locations of the components of the box by examining the summary statistics.
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 48.00 64.00 67.00 67.18 70.00 93.00
Confirm that the median and upper and lower quartiles reported in the numerical summary match those in the graph. The purpose of a boxplot is to provide a thumbnail sketch of a variable for the purpose of comparing across several categories. So we can, for example, compare the heights of men and women with
The notation here is new. The ~
character can be read versus or as a function of. So we’re asking R to give us a box plots of heights where the groups are defined by gender.
Next let’s consider a new variable that doesn’t show up directly in this data set: Body Mass Index (BMI) (http://en.wikipedia.org/wiki/Body_mass_index). BMI is a weight to height ratio and can be calculated as:
\[ BMI = \frac{weight~(lb)}{height~(in)^2} * 703 \]
703 is the approximate conversion factor to change units from metric (meters and kilograms) to imperial (inches and pounds).
The following two lines first make a new object called bmi
and then creates box plots of these values, defining groups by the variable cdc$genhlth
.
Notice that the first line above is just some arithmetic, but it’s applied to all 20,000 numbers in the cdc
data set. That is, for each of the 20,000 participants, we take their weight, divide by their height-squared and then multiply by 703. The result is 20,000 BMI values, one for each respondent. This is one reason why we like R: it lets us perform computations like this using very simple expressions.
Ans:
Overall there are plenty of outliers beyond the upper tukey fences (upper wiskers) for all health
types. For my case, I picked “very good health” and it still show high BMI levels. This tells me that
BMI is not a good discerning variable to use to indicate whether an individual is in good or poor health
Finally, let’s make some histograms. We can look at the histogram for the age of our respondents with the command
Histograms are generally a very good way to see the shape of a single distribution, but that shape can change depending on how the data is split between the different bins. You can control the number of bins by adding an argument to the command. In the next two lines, we first make a default histogram of bmi
and then one with 50 breaks.
Note that you can flip between plots that you’ve created by clicking the forward and backward arrows in the lower right region of RStudio, just above the plots. How do these two histograms compare?
At this point, we’ve done a good first pass at analyzing the information in the BRFSS questionnaire. We’ve found an interesting association between smoking and gender, and we can say something about the relationship between people’s assessment of their general health and their own BMI. We’ve also picked up essential computing tools – summary statistics, subsetting, and plots – that will serve us well throughout this course.
wtdesire
) and current weight (weight
). Create this new variable by subtracting the two columns in the data frame and assigning them to a new object called wdiff
.## [1] "integer"
## genhlth exerany hlthplan smoke100 height weight wtdesire age gender
## 1 good 0 1 0 70 175 175 77 m
## 2 good 0 1 1 64 125 115 33 f
## 3 good 1 1 1 60 105 105 49 f
## 4 good 1 1 0 66 132 124 42 f
## 5 very good 0 1 0 61 150 130 55 f
## 6 very good 1 1 0 64 114 114 55 f
## wdiff
## 1 0
## 2 -10
## 3 0
## 4 -8
## 5 -20
## 6 0
wdiff
? If an observation wdiff
is 0, what does this mean about the person’s weight and desired weight. What if wdiff
is positive or negative?Ans:
wdiff class is integer
If Wdiff = 0, -> means they are at their ideal weight. No need to go on diet
If Wdiff > 0, -> means they are Not at their ideal weight. Need gain weight; eat more
If Wdiff < 0, -> means they are Not at their ideal weight. Need lose weight; go on diet
wdiff
in terms of its center, shape, and spread, including any plots you use. What does this tell us about how people feel about their current weight?hist(
cdc$wdif,
col = 'skyblue3',
breaks = seq(min(cdc$wdif),max(cdc$wdif),by=((max(cdc$wdif) - min(cdc$wdif))/(length(cdc$wdif)-1))))
Ans:
The center is close to 0 because Most of the data hovers just under 0.
Shape is quite left skewed; more negatives than positive but a majority virtually 0
The spread is small and a majority of data is within Q2
This tells me people are mostly satisfied with their weight but with more desiring to lose weight than
to gain weight.
mdata <- subset(cdc, cdc$gender == "m")
fdata <- subset(cdc, cdc$gender == "f")
summary(mdata$weight)
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 78.0 165.0 185.0 189.3 210.0 500.0
## [1] 9569 10
## Min. 1st Qu. Median Mean 3rd Qu. Max.
## 68.0 128.0 145.0 151.7 170.0 495.0
## [1] 10431 10
## [1] 680
## [1] 68
ans:
Women desire to have lower weight than men
weight
and determine what proportion of the weights are within one standard deviation of the mean.## [1] 169.683
## [1] 40.08097
## [1] 20000 10
# for normal distribution => approximately 67% of population are within +/- 1 Standard Deviation
one_sd <-(.67*2000)/2
one_sd_freq<-((.67*2000)/2)/2000
one_sd
## [1] 670
## [1] 0.335
Ans:
Mean = 170
Std Dev = 40
Proportion of weights within 1 Std Dev = 670 or 0.335