Problem Set #3 - Diamonds Data Model
Shaun Irvin
2019-07-07
Initial Visualization
ggplot(diamonds, aes(cut,price)) + geom_boxplot()
ggplot(diamonds, aes(color,price)) + geom_boxplot()
ggplot(diamonds, aes(clarity,price)) + geom_boxplot()
ggplot(diamonds, aes(carat, price)) +
geom_hex(bins=50)
Subset Data and replot
diamonds2 <- diamonds %>%
filter(carat <= 2.5) %>%
mutate(lprice = log2(price), lcarat = log2(carat))
ggplot(diamonds2, aes(lcarat, lprice)) +
geom_hex(bins=50)
Simple model and visualization
mod_diamond <- lm(lprice ~ lcarat, data = diamonds2)
grid <- diamonds2 %>%
data_grid(carat = seq_range(carat, 20)) %>%
mutate(lcarat = log2(carat)) %>%
add_predictions(mod_diamond, "lprice") %>%
mutate(price = 2 ^ lprice)
ggplot(diamonds2, aes(carat, price)) +
geom_hex(bins = 50) +
geom_line(data = grid, color = "green", size = 1)
Add residuals and plot
diamonds2 <- diamonds2 %>%
add_residuals(mod_diamond, "lresid")
ggplot(diamonds2, aes(lcarat, lresid)) +
geom_hex(bins = 50)
ggplot(diamonds2, aes(cut,lresid)) + geom_boxplot()
ggplot(diamonds2, aes(color,lresid)) + geom_boxplot()
ggplot(diamonds2, aes(clarity,lresid)) + geom_boxplot()
Four parameter model and visualization
mod_diamond2 <- lm(
lprice ~ lcarat + color + cut + clarity, diamonds2
)
grid <- diamonds2 %>%
data_grid(cut, .model = mod_diamond2) %>%
add_predictions(mod_diamond2)
grid## # A tibble: 5 x 5
## cut lcarat color clarity pred
## <ord> <dbl> <chr> <chr> <dbl>
## 1 Fair -0.515 G VS2 11.2
## 2 Good -0.515 G VS2 11.3
## 3 Very Good -0.515 G VS2 11.4
## 4 Premium -0.515 G VS2 11.4
## 5 Ideal -0.515 G VS2 11.4ggplot(grid, aes(cut, pred)) +
geom_point()
Plot residuals of four parameter model
diamonds2 <- diamonds2 %>%
add_residuals(mod_diamond2, "lresid2")
ggplot(diamonds2, aes(lcarat, lresid2)) +
geom_hex(bins = 50)
diamonds2 %>%
filter(abs(lresid2) > 1) %>%
add_predictions(mod_diamond2) %>%
mutate(pred = round(2^pred)) %>%
select(price, pred, carat:table, x:z) %>%
arrange(price)## # A tibble: 16 x 11
## price pred carat cut color clarity depth table x y z
## <int> <dbl> <dbl> <ord> <ord> <ord> <dbl> <dbl> <dbl> <dbl> <dbl>
## 1 1013 264 0.25 Fair F SI2 54.4 64 4.3 4.23 2.32
## 2 1186 284 0.25 Premium G SI2 59 60 5.33 5.28 3.12
## 3 1186 284 0.25 Premium G SI2 58.8 60 5.33 5.28 3.12
## 4 1262 2644 1.03 Fair E I1 78.2 54 5.72 5.59 4.42
## 5 1415 639 0.35 Fair G VS2 65.9 54 5.57 5.53 3.66
## 6 1415 639 0.35 Fair G VS2 65.9 54 5.57 5.53 3.66
## 7 1715 576 0.32 Fair F VS2 59.6 60 4.42 4.34 2.61
## 8 1776 412 0.290 Fair F SI1 55.8 60 4.48 4.41 2.48
## 9 2160 314 0.34 Fair F I1 55.8 62 4.72 4.6 2.6
## 10 2366 774 0.3 Very Good D VVS2 60.6 58 4.33 4.35 2.63
## 11 3360 1373 0.51 Premium F SI1 62.7 62 5.09 4.96 3.15
## 12 3807 1540 0.61 Good F SI2 62.5 65 5.36 5.29 3.33
## 13 3920 1705 0.51 Fair F VVS2 65.4 60 4.98 4.9 3.23
## 14 4368 1705 0.51 Fair F VVS2 60.7 66 5.21 5.11 3.13
## 15 10011 4048 1.01 Fair D SI2 64.6 58 6.25 6.2 4.02
## 16 10470 23622 2.46 Premium E SI2 59.7 59 8.82 8.76 5.25Question #1
In the plot of lcarat vs. lprice, there are some bright vertical strips. What do they represent?
Answer: The bright vertical strips represent where the majority of the data points (price) lie for each size. Since most people probably buy diamonds at a recognizable size, these bright spots probably represent those sizes - .5 carat, .75 carat, 1 carat, etc. Diamond stores will most likely have many more of those rounded numbers.
Question #2
If log(price) = a_0 + a_1 * log(carat), what does that say about the relationship between price and carat?
Answer: If the log(carat) has a linear relationship with log(price), as shown by the linear equation above, then that would mean that carat has an exponential effect on the price. In other words, as the carat size increases, the price increases exponentially (not linearly).
Question #3
Extract the diamonds that have very high and very low residuals. Is there anything unusual about these diamonds? Are they particularly bad or good, or do you think these are pricing errors?
# Use this chunk to place your code for extracting the high and low residuals
diamonds2 %>%
filter(lresid2 > 1.5 | lresid2 < -1) %>%
add_predictions(mod_diamond2) %>%
mutate(pred = round(2^pred)) %>%
select(price, pred, carat:clarity) %>%
arrange(price)## # A tibble: 9 x 6
## price pred carat cut color clarity
## <int> <dbl> <dbl> <ord> <ord> <ord>
## 1 1013 264 0.25 Fair F SI2
## 2 1186 284 0.25 Premium G SI2
## 3 1186 284 0.25 Premium G SI2
## 4 1262 2644 1.03 Fair E I1
## 5 1715 576 0.32 Fair F VS2
## 6 1776 412 0.290 Fair F SI1
## 7 2160 314 0.34 Fair F I1
## 8 2366 774 0.3 Very Good D VVS2
## 9 10470 23622 2.46 Premium E SI2Answer: Using the filter() function, I set the cutoff for any residual greater than 1.5 and less than -1. This filters out the diamonds that are more than 2^1.5 (2.8x) and less than 2^-1 (1/2x) the predicted price. I wouldn’t say these represent anything particularly unusal, but you can definitely use this to find a few gems. For example, the last diamond listed for 10,470, but is predicted as 23,622 represent really good value, and is a diamond I would consider buying.
Question #4
Does the final model, mod_diamonds2, do a good job of predicting diamond prices? Would you trust it to tell you how much to spend if you were buying a diamond and why?
# Use this chunk to place your code for assessing how well the model predicts diamond prices
summary(mod_diamond2)##
## Call:
## lm(formula = lprice ~ lcarat + color + cut + clarity, data = diamonds2)
##
## Residuals:
## Min 1Q Median 3Q Max
## -1.17388 -0.12437 -0.00094 0.11920 2.78322
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 12.206978 0.001693 7211.806 < 2e-16 ***
## lcarat 1.886239 0.001124 1677.809 < 2e-16 ***
## color.L -0.633998 0.002910 -217.872 < 2e-16 ***
## color.Q -0.137580 0.002676 -51.409 < 2e-16 ***
## color.C -0.022072 0.002503 -8.819 < 2e-16 ***
## color^4 0.016570 0.002297 7.213 5.54e-13 ***
## color^5 -0.002828 0.002169 -1.304 0.192
## color^6 0.003533 0.001971 1.793 0.073 .
## cut.L 0.173866 0.003386 51.349 < 2e-16 ***
## cut.Q -0.050346 0.002980 -16.897 < 2e-16 ***
## cut.C 0.019129 0.002583 7.407 1.31e-13 ***
## cut^4 -0.002410 0.002066 -1.166 0.243
## clarity.L 1.308155 0.005179 252.598 < 2e-16 ***
## clarity.Q -0.334090 0.004839 -69.047 < 2e-16 ***
## clarity.C 0.178423 0.004140 43.093 < 2e-16 ***
## clarity^4 -0.088059 0.003298 -26.697 < 2e-16 ***
## clarity^5 0.035885 0.002680 13.389 < 2e-16 ***
## clarity^6 -0.001371 0.002327 -0.589 0.556
## clarity^7 0.048221 0.002051 23.512 < 2e-16 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 0.1916 on 53795 degrees of freedom
## Multiple R-squared: 0.9828, Adjusted R-squared: 0.9828
## F-statistic: 1.706e+05 on 18 and 53795 DF, p-value: < 2.2e-16Answer: By running a summary() function, we can see that the model is a very good fit for determining the price of a diamond by individually looking at each ‘C’. Almost all of the variables have significant p-values and the overall model F-statistic has a p-value of 2.2e-16. Furthermore, the R-squared is .9828, which indicates a high explanation of the variability of price. I would definitely trust this model to tell me how much to spend.