rm(list=ls())
load("more/mlb11.RData")runs and one of the other numerical variables? Plot this relationship using the variable at_bats as the predictor. Does the relationship look linear? If you knew a team’s at_bats, would you be comfortable using a linear model to predict the number of runs?Use a scatterplot to display this relationship. The relationship appears to be approximately linear; a linear model could predict the number of runs, but with dubious accuracy.
plot(mlb11$at_bats,mlb11$runs,col=c("darkred"))cor(mlb11$runs, mlb11$at_bats)## [1] 0.610627
With correlation coefficient .61 we see an approximate linear relationship of moderate (positive) strength with a few outliers. Data are concentrated at fewer than 5600 at-bats, which is logical.
plot_ss(x = mlb11$at_bats, y = mlb11$runs)## Click two points to make a line.
## Call:
## lm(formula = y ~ x, data = pts)
##
## Coefficients:
## (Intercept) x
## -2789.2429 0.6305
##
## Sum of Squares: 123721.9
plot_ss(x = mlb11$at_bats, y = mlb11$runs, showSquares = TRUE)## Click two points to make a line.
## Call:
## lm(formula = y ~ x, data = pts)
##
## Coefficients:
## (Intercept) x
## -2789.2429 0.6305
##
## Sum of Squares: 123721.9
plot_ss, choose a line that does a good job of minimizing the sum of squares. Run the function several times. What was the smallest sum of squares that you got? How does it compare to your neighbors?I was not prompted to select points and I am not sure what to do here. The sum of squares is 123721.9 from the earlier plots.
homeruns to predict runs. Using the estimates from the R output, write the equation of the regression line. What does the slope tell us in the context of the relationship between success of a team and its home runs?m2 <- lm(runs ~ homeruns, data = mlb11)
summary(m2)##
## Call:
## lm(formula = runs ~ homeruns, data = mlb11)
##
## Residuals:
## Min 1Q Median 3Q Max
## -91.615 -33.410 3.231 24.292 104.631
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 415.2389 41.6779 9.963 1.04e-10 ***
## homeruns 1.8345 0.2677 6.854 1.90e-07 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 51.29 on 28 degrees of freedom
## Multiple R-squared: 0.6266, Adjusted R-squared: 0.6132
## F-statistic: 46.98 on 1 and 28 DF, p-value: 1.9e-07
For y = runs and x = homeruns, y = 415.2389 + 1.8345 * x is our equation.
plot(mlb11$runs ~ mlb11$at_bats)
m1 <- lm(runs ~ at_bats, data = mlb11)
abline(m1)summary(m1)##
## Call:
## lm(formula = runs ~ at_bats, data = mlb11)
##
## Residuals:
## Min 1Q Median 3Q Max
## -125.58 -47.05 -16.59 54.40 176.87
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) -2789.2429 853.6957 -3.267 0.002871 **
## at_bats 0.6305 0.1545 4.080 0.000339 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 66.47 on 28 degrees of freedom
## Multiple R-squared: 0.3729, Adjusted R-squared: 0.3505
## F-statistic: 16.65 on 1 and 28 DF, p-value: 0.0003388
For y = runs and x = at_bats, y = -2789.2429 + 0.6305 * x is our equation.
runs <- -2789.2429 + (0.6305*5578)
runs## [1] 727.6861
The prediction would be 728; this is an overestimate if we consider the runs by the most similar case, the Phillies, with 5579 at-bats and 713 runs. We cannot calculate a residual for 5578 runs without an observed value, but we can estimate based on the 5579 at-bats and the 713 runs of the Phillies: 728 - 713 = 15.
plot(m1$residuals ~ mlb11$at_bats)
abline(h = 0, lty = 3) # adds a horizontal dashed line at y = 0There is no discernable pattern and the residuals appear to be evenly distributed about 0.
hist(m1$residuals)qqnorm(m1$residuals)
qqline(m1$residuals) # adds diagonal line to the normal prob plotThe histogram appears bimodal but roughly normal; otherwise the results appear approximately normal. The condition is met.
Constant variability:
This condition is met; variability around the plotline is fairly consistent among points.
mlb11 that you think might be a good predictor of runs. Produce a scatterplot of the two variables and fit a linear model. At a glance, does there seem to be a linear relationship?plot(mlb11$runs ~ mlb11$hits, col=c("darkred"), main = "Relationship between Runs and Hits", xlab = "Hits", ylab = "Runs")
m3 <- lm(runs ~ hits, data = mlb11)
abline(m3)summary(m3)##
## Call:
## lm(formula = runs ~ hits, data = mlb11)
##
## Residuals:
## Min 1Q Median 3Q Max
## -103.718 -27.179 -5.233 19.322 140.693
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) -375.5600 151.1806 -2.484 0.0192 *
## hits 0.7589 0.1071 7.085 1.04e-07 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 50.23 on 28 degrees of freedom
## Multiple R-squared: 0.6419, Adjusted R-squared: 0.6292
## F-statistic: 50.2 on 1 and 28 DF, p-value: 1.043e-07
The relationship does indeed appear to be linear.
runs and at_bats? Use the R\(^2\) values from the two model summaries to compare. Does your variable seem to predict runs better than at_bats? How can you tell?cor(mlb11$runs, mlb11$hits)## [1] 0.8012108
cor(mlb11$runs, mlb11$at_bats)## [1] 0.610627
With \(R^2\) value of .8012108, it appears that hits are a better predictor than at_bats; the higher the value (and closer to 1) the more accurate the predictor.
runs and each of the other five traditional variables. Which variable best predicts runs? Support your conclusion using the graphical and numerical methods we’ve discussed (for the sake of conciseness, only include output for the best variable, not all five).catbat<-cor(mlb11$runs, mlb11$at_bats)
chits<-cor(mlb11$runs, mlb11$hits)
chruns<-cor(mlb11$runs, mlb11$homeruns)
cbatavg<-cor(mlb11$runs, mlb11$bat_avg)
cskout<-cor(mlb11$runs, mlb11$strikeouts)
cstbase<-cor(mlb11$runs, mlb11$stolen_bases)
cwins<-cor(mlb11$runs, mlb11$wins)
lmcatbat<-summary(lm(mlb11$runs~mlb11$at_bats))$r.squared
lmchits<-summary(lm(mlb11$runs~mlb11$hits))$r.squared
lmchruns<-summary(lm(mlb11$runs~mlb11$homeruns))$r.squared
lmcbatavg<-summary(lm(mlb11$runs~mlb11$bat_avg))$r.squared
lmcskout<-summary(lm(mlb11$runs~mlb11$strikeouts))$r.squared
lmcstbase<-summary(lm(mlb11$runs~mlb11$stolen_bases))$r.squared
lmcwins<-summary(lm(mlb11$runs~mlb11$wins))$r.squared
rsq<-c(lmcatbat,lmchits,lmchruns,lmcbatavg,lmcskout,lmcstbase,lmcwins)
cor<-c(catbat,chits,chruns,cbatavg,cskout,cstbase,cwins)
name<-c("at_bats","hits","homeruns","bat_avg","strikeouts","stolen_bases","wins")
c<-cbind(name,cor,rsq)
#return the highest correlation coefficient.
answer<-c[order(-cor),]
answer## name cor rsq
## [1,] "bat_avg" "0.809985885461508" "0.656077134646863"
## [2,] "hits" "0.801210813231711" "0.641938767239419"
## [3,] "homeruns" "0.791557685558218" "0.626563569566283"
## [4,] "at_bats" "0.610627046720669" "0.372865390186805"
## [5,] "wins" "0.600808771113306" "0.360971179446681"
## [6,] "stolen_bases" "0.0539814103796295" "0.00291399266657394"
## [7,] "strikeouts" "-0.411531204450297" "0.169357932236313"
plot(mlb11$runs ~ mlb11$bat_avg, col=c("darkred"), main = "Relationship between Runs and Batting Average", xlab = "Batting Average", ylab = "Runs")
m4 <- lm(runs ~ bat_avg, data = mlb11)
abline(m4)summary(m4)##
## Call:
## lm(formula = runs ~ bat_avg, data = mlb11)
##
## Residuals:
## Min 1Q Median 3Q Max
## -94.676 -26.303 -5.496 28.482 131.113
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) -642.8 183.1 -3.511 0.00153 **
## bat_avg 5242.2 717.3 7.308 5.88e-08 ***
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 49.23 on 28 degrees of freedom
## Multiple R-squared: 0.6561, Adjusted R-squared: 0.6438
## F-statistic: 53.41 on 1 and 28 DF, p-value: 5.877e-08
Batting average appears to be the best predictor of runs. The batting average correlation coefficient is highest among the traditional variables.
runs? Using the limited (or not so limited) information you know about these baseball statistics, does your result make sense?cnob<-cor(mlb11$runs, mlb11$new_onbase)
cnslu<-cor(mlb11$runs, mlb11$new_slug)
cnobs<-cor(mlb11$runs, mlb11$new_obs)
lmnonb<-summary(lm(mlb11$runs~mlb11$new_onbase))$r.squared
lmnslu<-summary(lm(mlb11$runs~mlb11$new_slug))$r.squared
lmnobs<-summary(lm(mlb11$runs~mlb11$new_obs))$r.squared
rsq2<-c(lmcatbat,lmchits,lmchruns,lmcbatavg,lmcskout,lmcstbase,lmcwins,lmnonb,lmnslu,lmnobs)
cor2<-c(catbat,chits,chruns,cbatavg,cskout,cstbase,cwins,cnob,cnslu,cnobs)
name2<-c("at_bats","hits","homeruns","bat_avg","strikeouts","stolen_bases","wins","new_onbase","new_slug","new_obs")
c2<-cbind(name2,cor2,rsq2)
#return the highest correlation coefficient.
answer2<-c2[order(-cor2),]
answer2## name2 cor2 rsq2
## [1,] "new_obs" "0.966916297490023" "0.934927126351814"
## [2,] "new_slug" "0.947032400929154" "0.896870368409638"
## [3,] "new_onbase" "0.921469072430616" "0.849105251446139"
## [4,] "bat_avg" "0.809985885461508" "0.656077134646863"
## [5,] "hits" "0.801210813231711" "0.641938767239419"
## [6,] "homeruns" "0.791557685558218" "0.626563569566283"
## [7,] "at_bats" "0.610627046720669" "0.372865390186805"
## [8,] "wins" "0.600808771113306" "0.360971179446681"
## [9,] "stolen_bases" "0.0539814103796295" "0.00291399266657394"
## [10,] "strikeouts" "-0.411531204450297" "0.169357932236313"
Looking solely at correlation coefficients (and confirming with R-squared for each variable pair), the new statistics are better predictors overall.
plot(mlb11$runs ~ mlb11$new_obs, col=c("darkred"), main = "Relationship between Runs and New Obs", xlab = "New Obs", ylab = "Runs")
m5 <- lm(runs ~ new_obs, data = mlb11)
abline(m5)plot(mlb11$runs ~ mlb11$new_slug, col=c("darkred"), main = "Relationship between Runs and New Slug", xlab = "New Slug", ylab = "Runs")
m6 <- lm(runs ~ new_slug, data = mlb11)
abline(m6)plot(mlb11$runs ~ mlb11$new_onbase, col=c("darkred"), main = "Relationship between Runs and New Obs", xlab = "New OnBase", ylab = "Runs")
m7 <- lm(runs ~ new_onbase, data = mlb11)
abline(m7)Plots of each new variable vary from the regression line less than the traditional variables. I am not sure what variable “new_obs” is, but it is the best predictor of runs.
plot(m5$residuals ~ mlb11$new_obs)+
abline(h = 0, lty = 3)## integer(0)
The relationship appears linear; variability is constant and distribution appears to be normal.
hist(m5$residuals)Histogram indicates a nearly normal distribution, which is confirmed by the QQ pot below. Variability in distance to the line below is approximately constant; conditions are met.
qqnorm(m5$residuals)
qqline(m5$residuals)