1 The weights of steers in a herd are distributed normally. The variance is 40,000 and the mean steer weight is 1300 lbs. Find the probability that the weight of a randomly selected steer is greater than 979 lbs. (Round your answer to 4 decimal places)
round(pnorm(979, 1300, sqrt(40000), lower.tail = FALSE), 4)
## [1] 0.9458
Ans 94.57%
2 SVGA monitors manufactured by TSI Electronics have life spans that have a normal distribution with a variance of 1,960,000 and a mean life span of 11,000 hours. If a SVGA monitor is selected at random, find the probability that the life span of the monitor will be more than 8340 hours. (Round your answer to 4 decimal places)
round(pnorm(8340, 11000, sqrt(1960000), lower.tail = FALSE), 4)
## [1] 0.9713
Ans 97.13%
3 Suppose the mean income of firms in the industry for a year is 80 million dollars with a standard deviation of 3 million dollars. If incomes for the industry are distributed normally, what is the probability that a randomly selected firm will earn between 83 and 85 million dollars? (Round your answer to four decimal places)
round(pnorm(85, 80, 3) - pnorm(83, 80, 3), 4)
## [1] 0.1109
Ans 11.09%
round(qnorm(.86, 456, 123), 0)
## [1] 589
Ans 589
round(qnorm(0.07, mean=6.13, sd=0.06), 2)
## [1] 6.04
Ans 6.04
round(qnorm(0.93, mean=6.13, sd=0.06), 2)
## [1] 6.22
Ans 6.22
An English professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below the top 13% and above the bottom 55% C: Scores below the top 45% and above the bottom 20% D: Scores below the top 80% and above the bottom 9% F: Bottom 9% of scores
Scores on the test are normally distributed with a mean of 78.8 and a standard deviation of 9.8. Find the numerical limits for a C grade. Round your answers to the nearest whole number, if necessary.
round(qnorm(0.55,78.8,9.8),0)
## [1] 80
round(qnorm(0.20,78.8,9.8),0)
## [1] 71
Ans 71-80
round(qnorm(.55, 21.2, 5.4), 1)
## [1] 21.9
Ans 21.9
round(pbinom(10, 151, .09), 4)
## [1] 0.192
Ans .192
errmean <- 7/(sqrt(147))
round(pnorm(48.83, mean = 48, sd = errmean, lower.tail=FALSE),4)
## [1] 0.0753
Ans .0753
The quality control manager at a computer manufacturing company believes that the mean life of a computer is 91 months, with a standard deviation of 10. If he is correct, what is the probability that the mean of a sample of 68 computers would be greater than 93.54 months? (Round your answer to 4 decimal places)errmean <- 10/(sqrt(68))
round(pnorm(93.54, mean = 91, sd = errmean, lower.tail=FALSE),4)
## [1] 0.0181
Ans .0181
A director of reservations believes that 7% of the ticketed passengers are no-shows. If the director is right, what is the probability that the proportion of no-shows in a sample of 540 ticketed passengers would differ from the population proportion by less than 3%? (Round your answer to 4 decimal places)
Ans 51.53%
A bottle maker believes that 23% of his bottles are defective. If the bottle maker is accurate, what is the probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by greater than 4%? (Round your answer to 4 decimal places)
Ans 30.1%
A research company desires to know the mean consumption of beef per week among males over age 48. Suppose a sample of size 208 is drawn with x¯=3.9. Assume ??=0.8 . Construct the 80% confidence interval for the mean number of lb. of beef per week among males over 48. (Round your answers to 1 decimal place). Ans 38lb/week - 40lb/week
An economist wants to estimate the mean per capita income (in thousands of dollars) in a major city in California. Suppose a sample of size 7472 is drawn with x¯=16.6. Assume ??=11. Construct the 98% confidence interval for the mean per capita income. (Round your answers to 1 decimal place). Ans 16.3 - 16.9
Find the value of t such that 0.05 of the area under the curve is to the left of t. Assume the degrees of freedom equals 26. Choose the picture which best describes the problem.
round(qt(0.05, 26-1),4)
## [1] -1.7081
Ans Top right image
Step 1. Calculate the sample mean for the given sample data. (Round answer to 2 decimal places).
s <- c(383.6, 347.1, 371.9, 347.6, 325.8, 337)
round(mean(s),2)
## [1] 352.17
Step 2. Calculate the sample standard deviation for the given sample data. (Round answer to 2 decimal places).
round(sd(s, na.rm = FALSE),2)
## [1] 21.68
Step 3. Find the critical value that should be used in constructing the confidence interval. (Round answer to 3 decimal places). Ans -2.015
Step 4. Construct the 90% confidence interval. (Round answer to 2 decimal places). Ans 334.34 - 370
Step 1. Find the critical value that should be used in constructing the confidence interval. (Round answer to 3 decimal places). Ans -1.341
Step 2. Construct the 80% confidence interval. (Round answer to 1 decimal place). Ans 45.6 - 47.2
round((2.576 * 1.9 / 0.13)^2,0)
## [1] 1417
Ans 1417
round((1.960 * 1.9 / 0.19)^2,0)
## [1] 384
Ans 384
Step 1. Suppose a sample of 2089 tenth graders is drawn. Of the students sampled, 1734 read above the eighth grade level. Using the data, estimate the proportion of tenth graders reading at or below the eighth grade level. (Write your answer as a fraction or a decimal number rounded to 3 decimal places)
round(1 - (1734/2089),3)
## [1] 0.17
Step 2. Suppose a sample of 2089 tenth graders is drawn. Of the students sampled, 1734 read above the eighth grade level. Using the data, construct the 98% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. (Round your answers to 3 decimal places). Ans .124 - .216
round(156/474,3)
## [1] 0.329
Step 2. Suppose a sample of 474 tankers is drawn. Of these ships, 156 had spills. Using the data, construct the 95% confidence interval for the population proportion of oil tankers that have spills each month. (Round your answers to 3 decimal places). Ans .29 - .368