Suppose that you wanted to investigate whether there is a gender difference in musical preference among Plymouth State University students. To investigate this question, you took a small sample of PSU students. The sample data is stored in music.csv.

Import music.csv from Moodle under Date Files, and test the hypothesis as described as below.

# Load packages
library(dplyr)
library(ggplot2)
library(infer)

# Import data
music <- read.csv("/resources/rstudio/BusinessStatistics/Data/music03.csv")

Q1 How many male students in the sample reported to prefer Imagine Dragons?

14 male students prefer Imagine Dragons

music %>%
  # Count the rows by singer and sex
  count(sex, singer)
## # A tibble: 4 x 3
##   sex    singer      n
##   <fct>  <fct>   <int>
## 1 female Dragons     1
## 2 female Grande      3
## 3 male   Dragons    14
## 4 male   Grande      2

Interpretation

Q2 What percentage of male students in the sample reported to prefer Imagine Dragons?

87% of males prefer Imagine Dragons

# Find proportion of each sex who were Dragons
music %>%
  # Group by sex
  group_by(sex) %>%
  # Calculate proportion Dragons summary stat
  summarise(Dragons_prop = mean(singer == "Dragons"))
## # A tibble: 2 x 2
##   sex    Dragons_prop
##   <fct>         <dbl>
## 1 female        0.25 
## 2 male          0.875

Interpretation

Q3 What is the observed difference in the proportions between male and female (male - female) students in the sample?

There is a .625 differnece or, 62% difference in proportions between male and female.

Q4 What does this mean?

This means male students are more likely to prefer Imagine Dragons tahn female studnets by 62%

Q5 There might be a few negative permuted differences. What would a negative difference mean?

The negative difference means that the females preference is higher than the males because when you calculate propoertions the formula is male-female

# Calculate the observed difference in promotion rate
diff_orig <- music %>%
  # Group by sex
  group_by(sex) %>%
  # Summarize to calculate fraction Dragons
  summarise(prop_prom = mean(singer == "Dragons")) %>%
  # Summarize to calculate difference
  summarise(stat = diff(prop_prom)) %>% 
  pull()
    
# See the result
diff_orig # male - female
## [1] 0.625

# Create data frame of permuted differences in promotion rates
music_perm <- music %>%
  # Specify variables: singer (response variable) and sex (explanatory variable)
  specify(singer ~ sex, success = "Dragons") %>%
  # Set null hypothesis as independence: there is no gender musicrimination
  hypothesize(null = "independence") %>%
  # Shuffle the response variable, singer, one thousand times
  generate(reps = 1000, type = "permute") %>%
  # Calculate difference in proportion, male then female
  calculate(stat = "diff in props", order = c("male", "female")) # male - female
  
music_perm
## # A tibble: 1,000 x 2
##    replicate   stat
##        <int>  <dbl>
##  1         1  0.312
##  2         2  0.625
##  3         3  0    
##  4         4 -0.312
##  5         5  0    
##  6         6 -0.312
##  7         7 -0.312
##  8         8  0    
##  9         9  0    
## 10        10  0    
## # ... with 990 more rows

# Using permutation data, plot stat
ggplot(music_perm, aes(x = stat)) + 
  # Add a histogram layer
  geom_histogram(binwidth = 0.01) +
  # Using original data, add a vertical line at stat
  geom_vline(aes(xintercept = diff_orig), color = "red")

Interpretation (no need to revise)

Q6 What is the calculated p-value? Interpret.

The calucalted p-value is.7%

Q7 Based on the p-value you interpreted in Q6, would you reject the null hypothesis at the standard 5% significance level and accept the alternative hypothesis that male students are more likely to prefer Imagine Dragons?

Being that it is .7% it shows that is highly unlikely to see the observed difference by chance if there was no difference across gender. We would reject the null hypothesis being that it is highly less than 5%, and males are much likely to prefer imagine dragons than females are.

# Calculate the p-value for the original dataset
music_perm %>%
  get_p_value(obs_stat = diff_orig, direction = "greater")
## # A tibble: 1 x 1
##   p_value
##     <dbl>
## 1   0.034

Interpretation