Find the probability that among 10,000 random digits the digit 3 appears not more than 931 times.
n<-100000
digits<-rep(NA, n)
for(i in 1:n){
temp<-sample(c(0:9),10000, replace=TRUE)
count<-length(temp[temp==3])
digits[i]<-count
}
#histogram
hist(digits)
#probability
length(digits[digits<=931])/length(digits)
## [1] 0.01089
#standard deviation
sd(digits)
## [1] 30.03846