Let \(X\) be the number of times he hits - X has a Binomial distribution with n=300, p = 0.3
The probability to get a batting average of 0.267 or less is then the probability to have 80 hits or less in 300times at bats: \(P(X \leq 80) = B_{300,0.3}(80)\)
We use a normal approximation: \(B_{300,0.3} \approx N_{300*0.3, 300*0.3*0.7}\)
So,
\(P(X \leq 80) = B_{300,0.3}(80) \approx N_{90,63}(80)\)
\(= N_{0,1}(\frac{80-90}{\sqrt{63}}\)
\(= N_{0,1}(-1.26)\)
\(= 1- N_{0,1}(1.26)\)
\(= 1- 0.9131\)
\(=0.0869\)
The Rookie has a prob. of approx. 9% to show a batting averrage of 0.267, even if his true standard is 0.3. The low average is probably not due to bad luck. but rather poor performance.