Discussion week6

Week 6, Combinatorics / Conditional Prob

Fundamentals of Computational Mathematics

CUNY MSDS DATA 605, Fall 2018

Rose Koh

10/2/2018

Chapter 3,4

Section 4.1.8

P(A n B n C) = P({a}) = \(\frac {1}{8}\)

P(A) = P(B) = P(C) = \(\frac {1}{2}\)

Thus

P(A n B n C) = P(A)P(B)P(C) = \(\frac {1}{8}\)

P(A n B) = P(A n C) = P(B n C) = \(\frac {5}{16}\)

P(A)P(B) = P(A)P(C) = P(B)P(C) = \(\frac {1}{4}\)

No two of these events are independent.