1
#read in data
dta <- read.table("C:/Users/user/Dropbox/1062-Data_manage/0409/inclass/hs0.txt", header=T)
#只看race是asian的資料
dta.asian <- subset(dta, race=="asian")
#看math與socst的相關係數
r0 <- cor(dta.asian$math, dta.asian$socst)
#設定參數
cnt <- 0
nIter <- 1001解釋function
把read的順序重新排列,看他跟math的相關係數之間誰大誰小,如果重新排列後的read跟math的相關係數大於或等於math跟socst的相關係數,那就把cnt分數加一。最後跑1001次看總共有幾次是read跟math的相關係數比較大。
for (i in 1:nIter) {
new <- sample(dta.asian$read)
r <- cor(new, dta.asian$math)
if ( r0 <= r ) cnt <- cnt+1
}
cnt/nIter## [1] 0.03896104
試著把for拿掉
i=1
cnt=0
repeat{
new <- sample(dta.asian$read)
r <- cor(new, dta.asian$math)
i=i+1
if ( r0 <= r ) cnt <- cnt+1
if (i>=nIter)
break
}
cnt/nIter## [1] 0.03596404
2
這個function可以顯示出每次隨機的x,y的散布圖,依照nIter設置的數量產生出多少張圖。 (不在html中真的印出512張圖)
Brownian <- function(n = 11, pause = 0.05, nIter = 2, ...) {
x = rnorm(n)
y = rnorm(n)
i = 1
while (i <= nIter) {
plot(x, y, ...)
text(x, y, cex = 0.5)
x = x + rnorm(n)
y = y + rnorm(n)
Sys.sleep(pause)
i = i + 1
}
}
### test it
Brownian(xlim = c(-20, 20), ylim = c(-20, 20),
pch = 21, cex = 2, col = "cyan", bg = "lavender") 把while改成repeat
Brownian <- function(n = 11, pause = 0.05, nIter = 512, ...) {
x = rnorm(n)
y = rnorm(n)
i = 1
repeat {
plot(x, y, ...)
text(x, y, cex = 0.5)
x = x + rnorm(n)
y = y + rnorm(n)
Sys.sleep(pause)
i = i + 1
if (i>=nIter)
break
}
} 3
直接使用ifelse對亂數的m矩陣做調整
newsim<- function(n){
m <- matrix(nrow=n, ncol=2)
m[, 1] <- runif(n)
m[, 2] <- rnorm(n)
Gender <- ifelse(m[, 1]<0.5, "M", "F")
Height <- ifelse(m[, 1]<0.5, 170 + 7*m[, 2],160 + 5*m[, 2]) %>% round(2)
Person <- data.frame(Gender,Height)
return(Person)
}
newsim(10)## Gender Height
## 1 F 174.93
## 2 F 156.84
## 3 F 167.39
## 4 F 167.72
## 5 M 179.33
## 6 M 161.71
## 7 M 169.83
## 8 F 159.60
## 9 F 158.96
## 10 M 160.73