Data 605 Discussion 8

1. A die is rolled three times. Find the probability that the sum of the outcomes is

1. greater than 9

probs <- rep(0,1) 
  for (d1 in 1:6)    
    for (d2 in 1:6)     
      for (d3 in 1:6) {       
          s <- d1 + d2 + d3       
            probs[1] <- probs[1] + ((s > 9)) }
probs <- probs / 6^3 
print(probs)

## [1] 0.625

2. an odd number

Since the dice is fair, you have \(1/2\) chance of getting an odd number on each roll. The probability is \(.5\)