HW1 - Problem 6

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6-1 Find the expression of \(\gamma_1(x_2)\).

透過題目的敘述可以將 2 式做整理，分為 \(x_1\) 項一類，剩下一類

因此 \(\gamma_0(x_2) = \beta_0+\beta_2x_2\)

\(\gamma_1(x_2)x_1=(\beta_1+\beta_3x_2)x_1\), \(\gamma_1(x_2)=\beta_1+\beta_3x_2\)

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6-2 Use 1 to interpretate the meaning of \(\beta_3\).

\(\gamma_0(x_2) = \beta_0+\beta_2x_2\)

\(\gamma_1(x_2)=\beta_1+\beta_3x_2\)

\(\beta_3\) 為 \(x_1\) 與 \(x_2\) 的交互作用