setwd("~/Desktop/5 SRM Kashish Mukheja/Downoad content")
Titanic.df<-read.csv(paste("Titanic Data.csv",sep=""))
View(Titanic.df)
mytable<-with(Titanic.df,table(Survived))
summary(mytable)
## Number of cases in table: 889
## Number of factors: 1
The total number of passengers on board the Titanic:889
mytable<-with(Titanic.df,table(Survived))
mytable
## Survived
## 0 1
## 549 340
The number of passengers who survived the sinking of the Titanic:340
prop.table(mytable)*100
## Survived
## 0 1
## 61.75478 38.24522
The percentage of passengers who survived the sinking of the Titanic:38.24522
mytable1<-xtabs(~Survived+Pclass,data=Titanic.df)
mytable1
## Pclass
## Survived 1 2 3
## 0 80 97 372
## 1 134 87 119
The number of first-class passengers who survived the sinking of the Titanic:134
prop.table(mytable1)*100
## Pclass
## Survived 1 2 3
## 0 8.998875 10.911136 41.844769
## 1 15.073116 9.786277 13.385827
The percentage of first-class passengers who survived the sinking of the Titanic:15.073116
mytable2<-xtabs(~Survived+Pclass+Sex,data=Titanic.df)
mytable2
## , , Sex = female
##
## Pclass
## Survived 1 2 3
## 0 3 6 72
## 1 89 70 72
##
## , , Sex = male
##
## Pclass
## Survived 1 2 3
## 0 77 91 300
## 1 45 17 47
The number of females from First-Class who survived the sinking of the Titanic:89
ftable(prop.table(margin.table(mytable2,c(1,3))))*100
## Sex female male
## Survived
## 0 9.111361 52.643420
## 1 25.984252 12.260967
The percentage of survivors who were female:25.984252
mytable3<-xtabs(~Survived+Sex,data=Titanic.df)
prop.table(mytable3,2)*100
## Sex
## Survived female male
## 0 25.96154 81.10919
## 1 74.03846 18.89081
The percentage of females on board the Titanic who survived:74.03846
Hypothesis: The proportion of females onboard who survived the sinking of the Titanic was higher than the proportion of males onboard who survived the sinking of the Titanic.
mytable4<-xtabs(~Survived+Sex,data=Titanic.df)
addmargins(mytable4)
## Sex
## Survived female male Sum
## 0 81 468 549
## 1 231 109 340
## Sum 312 577 889
chisq.test(mytable4)
##
## Pearson's Chi-squared test with Yates' continuity correction
##
## data: mytable4
## X-squared = 258.43, df = 1, p-value < 2.2e-16
Since the p-value<0.01, so we reject the null Hypothesis.