Store24
Aswathy Gunadeep
18 December 2017
Store24: Employee Retention Cas Study
This is a case study based on the case “Store24 (A): Managing Employee Retention”.
Reading and Viewing the Store24 Database
setwd("D:/desktop/Data Analytics internship-sameer mathur/work/datasets")
store.df<-read.csv(paste("Store24.csv", sep=""))
View(store.df)2c: Summary statistics of Store24 Data-database of sample stores.
summary(store.df)## store Sales Profit MTenure
## Min. : 1.0 Min. : 699306 Min. :122180 Min. : 0.00
## 1st Qu.:19.5 1st Qu.: 984579 1st Qu.:211004 1st Qu.: 6.67
## Median :38.0 Median :1127332 Median :265014 Median : 24.12
## Mean :38.0 Mean :1205413 Mean :276314 Mean : 45.30
## 3rd Qu.:56.5 3rd Qu.:1362388 3rd Qu.:331314 3rd Qu.: 50.92
## Max. :75.0 Max. :2113089 Max. :518998 Max. :277.99
## CTenure Pop Comp Visibility
## Min. : 0.8871 Min. : 1046 Min. : 1.651 Min. :2.00
## 1st Qu.: 4.3943 1st Qu.: 5616 1st Qu.: 3.151 1st Qu.:3.00
## Median : 7.2115 Median : 8896 Median : 3.629 Median :3.00
## Mean : 13.9315 Mean : 9826 Mean : 3.788 Mean :3.08
## 3rd Qu.: 17.2156 3rd Qu.:14104 3rd Qu.: 4.230 3rd Qu.:4.00
## Max. :114.1519 Max. :26519 Max. :11.128 Max. :5.00
## PedCount Res Hours24 CrewSkill
## Min. :1.00 Min. :0.00 Min. :0.00 Min. :2.060
## 1st Qu.:2.00 1st Qu.:1.00 1st Qu.:1.00 1st Qu.:3.225
## Median :3.00 Median :1.00 Median :1.00 Median :3.500
## Mean :2.96 Mean :0.96 Mean :0.84 Mean :3.457
## 3rd Qu.:4.00 3rd Qu.:1.00 3rd Qu.:1.00 3rd Qu.:3.655
## Max. :5.00 Max. :1.00 Max. :1.00 Max. :4.640
## MgrSkill ServQual
## Min. :2.957 Min. : 57.90
## 1st Qu.:3.344 1st Qu.: 78.95
## Median :3.589 Median : 89.47
## Mean :3.638 Mean : 87.15
## 3rd Qu.:3.925 3rd Qu.: 99.90
## Max. :4.622 Max. :100.00There are 75 stores and the average Fiscal Year 2000 profit is 276314 dollars.
2d: mean and standard deviation of tenure of crew and manager
#MEAN#
apply(store.df[,3:5], FUN=mean, MARGIN=2)## Profit MTenure CTenure
## 276313.61333 45.29644 13.93150#STANDARD DEVIATION#
apply(store.df[,3:5], FUN=sd, MARGIN=2)## Profit MTenure CTenure
## 89404.07634 57.67155 17.697522e: sorting and subsetting in R
#Top 10 most profitable stores#
newstore <- store.df[order(-store.df$Profit),]
newstore[1:10,1:5]## store Sales Profit MTenure CTenure
## 74 74 1782957 518998 171.09720 29.519510
## 7 7 1809256 476355 62.53080 7.326488
## 9 9 2113089 474725 108.99350 6.061602
## 6 6 1703140 469050 149.93590 11.351130
## 44 44 1807740 439781 182.23640 114.151900
## 2 2 1619874 424007 86.22219 6.636550
## 45 45 1602362 410149 47.64565 9.166325
## 18 18 1704826 394039 239.96980 33.774130
## 11 11 1583446 389886 44.81977 2.036961
## 47 47 1665657 387853 12.84790 6.636550#Bottom 10 least profitable stores#
newstore <- store.df[order(store.df$Profit),]
newstore[1:10,1:5]## store Sales Profit MTenure CTenure
## 57 57 699306 122180 24.3485700 2.956879
## 66 66 879581 146058 115.2039000 3.876797
## 41 41 744211 147327 14.9180200 11.926080
## 55 55 925744 147672 6.6703910 18.365500
## 32 32 828918 149033 36.0792600 6.636550
## 13 13 857843 152513 0.6571813 1.577002
## 54 54 811190 159792 6.6703910 3.876797
## 52 52 1073008 169201 24.1185600 3.416838
## 61 61 716589 177046 21.8184200 13.305950
## 37 37 1202917 187765 23.1985000 1.3470232g: scatterplot of Profit vs Manager tenure
library(car)
scatterplot(store.df$MTenure, store.df$Profit, main = "scatterplot of Profit vs Manager Tenure", xlab = "Manager Tenure", ylab = "Profit")
2h: scatterplot of Profit vs Crew tenure
library(car)
scatterplot(store.df$CTenure, store.df$Profit, xlab = "CTenure", ylab = "Profit", main = "scatterplot of Profit vs CTenure")
2i: Correlation Matrix
corr1 <- cor(store.df)
round(corr1, 2)## store Sales Profit MTenure CTenure Pop Comp Visibility
## store 1.00 -0.23 -0.20 -0.06 0.02 -0.29 0.03 -0.03
## Sales -0.23 1.00 0.92 0.45 0.25 0.40 -0.24 0.13
## Profit -0.20 0.92 1.00 0.44 0.26 0.43 -0.33 0.14
## MTenure -0.06 0.45 0.44 1.00 0.24 -0.06 0.18 0.16
## CTenure 0.02 0.25 0.26 0.24 1.00 0.00 -0.07 0.07
## Pop -0.29 0.40 0.43 -0.06 0.00 1.00 -0.27 -0.05
## Comp 0.03 -0.24 -0.33 0.18 -0.07 -0.27 1.00 0.03
## Visibility -0.03 0.13 0.14 0.16 0.07 -0.05 0.03 1.00
## PedCount -0.22 0.42 0.45 0.06 -0.08 0.61 -0.15 -0.14
## Res -0.03 -0.17 -0.16 -0.06 -0.34 -0.24 0.22 0.02
## Hours24 0.03 0.06 -0.03 -0.17 0.07 -0.22 0.13 0.05
## CrewSkill 0.05 0.16 0.16 0.10 0.26 0.28 -0.04 -0.20
## MgrSkill -0.07 0.31 0.32 0.23 0.12 0.08 0.22 0.07
## ServQual -0.32 0.39 0.36 0.18 0.08 0.12 0.02 0.21
## PedCount Res Hours24 CrewSkill MgrSkill ServQual
## store -0.22 -0.03 0.03 0.05 -0.07 -0.32
## Sales 0.42 -0.17 0.06 0.16 0.31 0.39
## Profit 0.45 -0.16 -0.03 0.16 0.32 0.36
## MTenure 0.06 -0.06 -0.17 0.10 0.23 0.18
## CTenure -0.08 -0.34 0.07 0.26 0.12 0.08
## Pop 0.61 -0.24 -0.22 0.28 0.08 0.12
## Comp -0.15 0.22 0.13 -0.04 0.22 0.02
## Visibility -0.14 0.02 0.05 -0.20 0.07 0.21
## PedCount 1.00 -0.28 -0.28 0.21 0.09 -0.01
## Res -0.28 1.00 -0.09 -0.15 -0.03 0.09
## Hours24 -0.28 -0.09 1.00 0.11 -0.04 0.06
## CrewSkill 0.21 -0.15 0.11 1.00 -0.02 -0.03
## MgrSkill 0.09 -0.03 -0.04 -0.02 1.00 0.36
## ServQual -0.01 0.09 0.06 -0.03 0.36 1.002j(1): correlation between Profit and MTenure
corr2 <- cor(store.df$Profit, store.df$MTenure)
round(corr2, 2)## [1] 0.442j(2): correlation between Profit and CTenure
corr3 <- cor(store.df$Profit, store.df$CTenure)
round(corr3, 2)## [1] 0.262k: corrgram
library(corrgram)
corrgram(store.df, upper.panel = panel.pie, main="Corrgram of store variables")
Managerially Relavant Correlations Increasing order of correlation value with the profit:
ServQual, Pop, MTenure, PedCount and Sales.
2l(1): Pearson’s Correlation test on the correlation between Profit and MTenure
cor.test(store.df$Profit,store.df$MTenure)##
## Pearson's product-moment correlation
##
## data: store.df$Profit and store.df$MTenure
## t = 4.1731, df = 73, p-value = 8.193e-05
## alternative hypothesis: true correlation is not equal to 0
## 95 percent confidence interval:
## 0.2353497 0.6055175
## sample estimates:
## cor
## 0.4388692p-Value is lesser than 0.05. Hence there is a strong correlation between the two variables.
2l(2): Pearson’s Correlation test on the correlation between Profit and CTenure
cor.test(store.df$Profit ,store.df$CTenure)##
## Pearson's product-moment correlation
##
## data: store.df$Profit and store.df$CTenure
## t = 2.2786, df = 73, p-value = 0.02562
## alternative hypothesis: true correlation is not equal to 0
## 95 percent confidence interval:
## 0.03262507 0.45786339
## sample estimates:
## cor
## 0.2576789p-Value is lesser than 0.05. There is some correlation between the two variables.
2m: regression of Profit on {MTenure, CTenure Comp, Pop, PedCount, Res, Hours24, Visibility}
fit <- lm(formula = Profit ~ MTenure + CTenure + Comp + Pop + PedCount + Res + Hours24 + Visibility, data = store.df )
summary(fit)##
## Call:
## lm(formula = Profit ~ MTenure + CTenure + Comp + Pop + PedCount +
## Res + Hours24 + Visibility, data = store.df)
##
## Residuals:
## Min 1Q Median 3Q Max
## -105789 -35946 -7069 33780 112390
##
## Coefficients:
## Estimate Std. Error t value Pr(>|t|)
## (Intercept) 7610.041 66821.994 0.114 0.909674
## MTenure 760.993 127.086 5.988 9.72e-08 ***
## CTenure 944.978 421.687 2.241 0.028400 *
## Comp -25286.887 5491.937 -4.604 1.94e-05 ***
## Pop 3.667 1.466 2.501 0.014890 *
## PedCount 34087.359 9073.196 3.757 0.000366 ***
## Res 91584.675 39231.283 2.334 0.022623 *
## Hours24 63233.307 19641.114 3.219 0.001994 **
## Visibility 12625.447 9087.620 1.389 0.169411
## ---
## Signif. codes: 0 '***' 0.001 '**' 0.01 '*' 0.05 '.' 0.1 ' ' 1
##
## Residual standard error: 56970 on 66 degrees of freedom
## Multiple R-squared: 0.6379, Adjusted R-squared: 0.594
## F-statistic: 14.53 on 8 and 66 DF, p-value: 5.382e-12Statistically significant variables: MTenure , CTenure, Comp, Pop , PedCount , Res , Hours24.
Statistically insignificant variables: Visibility
fit$coefficients## (Intercept) MTenure CTenure Comp Pop
## 7610.041452 760.992734 944.978026 -25286.886662 3.666606
## PedCount Res Hours24 Visibility
## 34087.358789 91584.675234 63233.307162 12625.447050- expected change in the Profit at a store, if the Manager’s tenure i.e. number of months of experience with Store24, increases by one month is 760.992734 dollars.
- expected change in the Profit at a store, if the Crew’s tenure i.e. number of months of experience with Store24, increases by one month is 944.978026 dollars.
Executive Summary
Executive Summary:
- From the above analysis, the profit of a store depends upon both the manager’s and crew’s tenure.
- From the scatterplots, corrgram and the correlation matrix , it is clear that the profit depends more on the manager’s tenure than the Crew tenure.
- The stores which run 24hours tend to bring losses.
- The multiple r-squared value is 0.6379 that means that 63.79% of the variance in the dependent variable that is profit is explained by the independent variables.
- The p-vale of the F-statistic is 5.382e-12 which is significantly less than 0.05 and close to zero that imples the regression model is a good one and we can depend on it to make decisions.