10.2

7.)

a)Z=2.31, Level of Significance=1.645. So, Since 2.31>1.645, we reject the Null hypothesis and conclude that p>0.3
  
b) P value=0.0104. Since Pval<0.05, reject the null hypothesis and conclude that p>0.3

11.)

a) z=-1.49. Level of Significance= -1.96, 1.96. So, we do not reject the Null hypothesis because the test statistic does not fall in the critical regions. 
  
b) P Value=0.1362. The pval>signifigance level (.05), so fail to reject the null hypothesis. 

 

  1. Z=.65, Critical Value=2.33 Since test statistic is less than the critial value, fail to reject the null hypothesis. Pvalue=.2578 which is greater than the signifigance level (.01), so reject in this case. All in all, do not reject the null hypothesis. There is not enough evidence to conclide that more than 1.9% of Lipitor users expericen fluelike symptoms.

  2. Z=.69, Pvalue=.2460. The pvalue is greater than the signifigance level (.01), So, fail to reject the null hypothesis There is not enough evidence to conclude that the percentage is higher than .94.

 

10.3

1.)

a) 2.602
  
b) -1.729
  
c) 2.179, -2.179

12.)

a) Ho:m=63.7 inches.
   
   H1:m>63.7 inches. 
  
b) If the p-value is .35, we expect that there is a 0.35 probability of obtaining a sample mean of 63.9 inches or taller from a population whose mean is 63.7 inches. 
  
c) Do not reject the null hypothesis. The mean height of women 20 years and older was 63.7 inches. 

13.)

a) Ho:m=22.

   H1:m>22
  
b) It is given in the problem that the sample is random and is bigger than 30 so it is reasonable to assume that the sampled values are independent. 
  
c) t=2.1757, Critical Value=1.660. Since 2.1757>1.660, reject the null hypothesis. 

d) We can conclude that the results suggest that students who complete the core curricuum are ready for college level mathematics. They are scoring above 22 on the math portion of the ACT.

14.)

a) Ho: m=501

   H1:m<501

b) It is given in the problem that the sample is random and is larger than 30, according to the central limit theorem, the distribution of Xbar is approx normal. 
  
c) t=-1.379, Critical Value=-1.29. The test statistic is less than the critical value and it falls into the critical region. So we reject the null hypothesis. 

d) We conclude that the results suggest that students who learn english and another language, simultaneously score worse on the SAT critical region section. 
  1. Test Statistic: -4.553. Critical Value=-2.718. Since the test statistic is less than the critical value, reject the null hypothesis. Hoppocampal volumes in alcoholic adolescents are less than the normal volume of 9.02cm3.