7.)
a) z0 = 2.31 > z0.05 = 1.645. Reject the null hypothesis.
b) P-value = 0.010411.)
a) z0 = -1.49 is between -z0.025 = -1.96 and z0.025 = 1.96, so we faliled to reject the null hypothesis.
b) P-value = 0.1362
z0 = 0.65 < z0.01 = 2.33. Fail to reject null hypothesis.
P-value = 0.2643 > a = 0.01, Fail to reject null hypothesis.
1.)
a) t = 2.602
b) t = -1.729
c) -t0.025 = -2.179, t0.025 = 2.17912.)
a) Ho: M = 63.7
H1: M > 63.7
b) With P-value = 0.35, we expect that about 35 samples to result in a mean as extreme or more extreme than the one observed.
c) P-value = 0.35 > a = 0.10, there is sufficient evident to conclude that women 20 years of age or older are not taller than 63.7 inches. We fail to reject the null hypothesis. 13.)
a) Ho: M = 22
H1: M > 22
b) Sample is random. Sample size is large, n = 200 > 30. Scores are independent, because we can assume that the sample size is small relative to the population.
c) Classical method: t0 = 2.18 > t0.05 = 1.660. Reject the null hypothesis.
d) There is sufficient evidence to conclude that the students who complete core corriculum are scoring above 22 on the math section of the ACT. 14.)
a) Ho: M = 501
H1: M < 501
b) Sample is random. Sample size is large, n = 100 > 30. Scores are independent, because we can assume that the sample size is small relative to the population.
c) Classic method: t = -1.38 < t0.1 = -1.290. Reject the null hypothesis.
d) There is sufficient evident to conclude that test takers who learned English and another language simultaneously are scoring worse on the SAT Critical Reading exam.