Objectives

The objectives of this problem set is to orient you to a number of activities in R. And to conduct a thoughtful exercise in appreciating the importance of data visualization. For each question create a code chunk or text response that completes/answers the activity or question requested. Finally, upon completion name your final output .html file as: YourName_ANLY512-Section-Year-Semester.html and upload it to the “Problem Set 2” assignmenet on Moodle.

Questions

  1. Anscombes quartet is a set of 4 \(x,y\) data sets that were published by Francis Anscombe in a 1973 paper Graphs in statistical analysis. For this first question load the anscombe data that is part of the library(datasets) in R. And assign that data to a new object called data.
library(datasets)
data <- anscombe
data
##    x1 x2 x3 x4    y1   y2    y3    y4
## 1  10 10 10  8  8.04 9.14  7.46  6.58
## 2   8  8  8  8  6.95 8.14  6.77  5.76
## 3  13 13 13  8  7.58 8.74 12.74  7.71
## 4   9  9  9  8  8.81 8.77  7.11  8.84
## 5  11 11 11  8  8.33 9.26  7.81  8.47
## 6  14 14 14  8  9.96 8.10  8.84  7.04
## 7   6  6  6  8  7.24 6.13  6.08  5.25
## 8   4  4  4 19  4.26 3.10  5.39 12.50
## 9  12 12 12  8 10.84 9.13  8.15  5.56
## 10  7  7  7  8  4.82 7.26  6.42  7.91
## 11  5  5  5  8  5.68 4.74  5.73  6.89
  1. Summarise the data by calculating the mean, variance, for each column and the correlation between each pair (eg. x1 and y1, x2 and y2, etc) (Hint: use the fBasics() package!)
library(fBasics)
## Loading required package: timeDate
## Loading required package: timeSeries
## 
## Rmetrics Package fBasics
## Analysing Markets and calculating Basic Statistics
## Copyright (C) 2005-2014 Rmetrics Association Zurich
## Educational Software for Financial Engineering and Computational Science
## Rmetrics is free software and comes with ABSOLUTELY NO WARRANTY.
## https://www.rmetrics.org --- Mail to: info@rmetrics.org
# Mean of each column 
column_mean <- colMeans(data)
column_mean
##       x1       x2       x3       x4       y1       y2       y3       y4 
## 9.000000 9.000000 9.000000 9.000000 7.500909 7.500909 7.500000 7.500909
# Variance of each column
column_variance <- colVars(data)
column_variance
##        x1        x2        x3        x4        y1        y2        y3 
## 11.000000 11.000000 11.000000 11.000000  4.127269  4.127629  4.122620 
##        y4 
##  4.123249
# Correlation between each pair of x and y
correl_x1y1 <- correlationTest(data$x1,data$y1,method = c("pearson","kendall","spearman"),title = "Correlation between x1 and y1")
correl_x1y1
## 
## Title:
##  Correlation between x1 and y1
## 
## Test Results:
##   PARAMETER:
##     Degrees of Freedom: 9
##   SAMPLE ESTIMATES:
##     Correlation: 0.8164
##   STATISTIC:
##     t: 4.2415
##   P VALUE:
##     Alternative Two-Sided: 0.00217 
##     Alternative      Less: 0.9989 
##     Alternative   Greater: 0.001085 
##   CONFIDENCE INTERVAL:
##     Two-Sided: 0.4244, 0.9507
##          Less: -1, 0.9388
##       Greater: 0.5113, 1
## 
## Description:
##  Tue Nov 14 23:48:25 2017
correl_x2y2 <- correlationTest(data$x1,data$y1,method = c("pearson","kendall","spearman"),title = "Correlation between x2 and y2")
correl_x2y2
## 
## Title:
##  Correlation between x2 and y2
## 
## Test Results:
##   PARAMETER:
##     Degrees of Freedom: 9
##   SAMPLE ESTIMATES:
##     Correlation: 0.8164
##   STATISTIC:
##     t: 4.2415
##   P VALUE:
##     Alternative Two-Sided: 0.00217 
##     Alternative      Less: 0.9989 
##     Alternative   Greater: 0.001085 
##   CONFIDENCE INTERVAL:
##     Two-Sided: 0.4244, 0.9507
##          Less: -1, 0.9388
##       Greater: 0.5113, 1
## 
## Description:
##  Tue Nov 14 23:48:25 2017
correl_x3y3 <- correlationTest(data$x1,data$y1,method = c("pearson","kendall","spearman"),title = "Correlation between x3 and y3")
correl_x3y3
## 
## Title:
##  Correlation between x3 and y3
## 
## Test Results:
##   PARAMETER:
##     Degrees of Freedom: 9
##   SAMPLE ESTIMATES:
##     Correlation: 0.8164
##   STATISTIC:
##     t: 4.2415
##   P VALUE:
##     Alternative Two-Sided: 0.00217 
##     Alternative      Less: 0.9989 
##     Alternative   Greater: 0.001085 
##   CONFIDENCE INTERVAL:
##     Two-Sided: 0.4244, 0.9507
##          Less: -1, 0.9388
##       Greater: 0.5113, 1
## 
## Description:
##  Tue Nov 14 23:48:25 2017
correl_x4y4 <- correlationTest(data$x1,data$y1,method = c("pearson","kendall","spearman"),title = "Correlation between x4 and y4")
correl_x4y4
## 
## Title:
##  Correlation between x4 and y4
## 
## Test Results:
##   PARAMETER:
##     Degrees of Freedom: 9
##   SAMPLE ESTIMATES:
##     Correlation: 0.8164
##   STATISTIC:
##     t: 4.2415
##   P VALUE:
##     Alternative Two-Sided: 0.00217 
##     Alternative      Less: 0.9989 
##     Alternative   Greater: 0.001085 
##   CONFIDENCE INTERVAL:
##     Two-Sided: 0.4244, 0.9507
##          Less: -1, 0.9388
##       Greater: 0.5113, 1
## 
## Description:
##  Tue Nov 14 23:48:25 2017
  1. Create scatter plots for each \(x, y\) pair of data.
plot_x1y1 <- plot(data$x1,data$y1, main = "x1 and y1")

plot_x2y2 <- plot(data$x2,data$y2, main = "x2 and y2")

plot_x3y3 <- plot(data$x3,data$y3, main = "x3 and y3")

plot_x4y4 <- plot(data$x4,data$y4, main = "x4 and y4")

  1. Now change the symbols on the scatter plots to solid circles and plot them together as a 4 panel graphic
attach(data)

par(mfrow = c(2,2))

plot(data$x1,data$y1, main = "x1 and y1", pch = 16)

plot(data$x2,data$y2, main = "x2 and y2", pch = 16)

plot(data$x3,data$y3, main = "x3 and y3", pch = 16)

plot(data$x4,data$y4, main = "x4 and y4", pch = 16)

  1. Now fit a linear model to each data set using the lm() function.
lm_x1y1 <- lm(data$y1~data$x1)
lm_x1y1
## 
## Call:
## lm(formula = data$y1 ~ data$x1)
## 
## Coefficients:
## (Intercept)      data$x1  
##      3.0001       0.5001
lm_x2y2 <- lm(data$y2~data$x2)
lm_x2y2
## 
## Call:
## lm(formula = data$y2 ~ data$x2)
## 
## Coefficients:
## (Intercept)      data$x2  
##       3.001        0.500
lm_x3y3 <- lm(data$y3~data$x3)
lm_x3y3
## 
## Call:
## lm(formula = data$y3 ~ data$x3)
## 
## Coefficients:
## (Intercept)      data$x3  
##      3.0025       0.4997
lm_x4y4 <- lm(data$y4~data$x4)
lm_x4y4
## 
## Call:
## lm(formula = data$y4 ~ data$x4)
## 
## Coefficients:
## (Intercept)      data$x4  
##      3.0017       0.4999
  1. Now combine the last two tasks. Create a four panel scatter plot matrix that has both the data points and the regression lines. (hint: the model objects will carry over chunks!)
attach(data)
## The following objects are masked from data (pos = 3):
## 
##     x1, x2, x3, x4, y1, y2, y3, y4
par(mfrow = c(2,2))

plot(data$x1,data$y1, main = "x1 and y1", pch = 16, abline(lm_x1y1))

plot(data$x2,data$y2, main = "x2 and y2", pch = 16, abline(lm_x2y2))

plot(data$x3,data$y3, main = "x3 and y3", pch = 16, abline(lm_x3y3))

plot(data$x4,data$y4, main = "x4 and y4", pch = 16, abline(lm_x4y4))

  1. Now compare the model fits for each model object.
summary(lm_x1y1)

Call: lm(formula = data\(y1 ~ data\)x1)

Residuals: Min 1Q Median 3Q Max -1.92127 -0.45577 -0.04136 0.70941 1.83882

Coefficients: Estimate Std. Error t value Pr(>|t|)
(Intercept) 3.0001 1.1247 2.667 0.02573 * data$x1 0.5001 0.1179 4.241 0.00217 ** — Signif. codes: 0 ‘’ 0.001 ’’ 0.01 ’’ 0.05 ‘.’ 0.1 ‘’ 1

Residual standard error: 1.237 on 9 degrees of freedom Multiple R-squared: 0.6665, Adjusted R-squared: 0.6295 F-statistic: 17.99 on 1 and 9 DF, p-value: 0.00217

summary(lm_x2y2)

Call: lm(formula = data\(y2 ~ data\)x2)

Residuals: Min 1Q Median 3Q Max -1.9009 -0.7609 0.1291 0.9491 1.2691

Coefficients: Estimate Std. Error t value Pr(>|t|)
(Intercept) 3.001 1.125 2.667 0.02576 * data$x2 0.500 0.118 4.239 0.00218 ** — Signif. codes: 0 ‘’ 0.001 ’’ 0.01 ’’ 0.05 ‘.’ 0.1 ‘’ 1

Residual standard error: 1.237 on 9 degrees of freedom Multiple R-squared: 0.6662, Adjusted R-squared: 0.6292 F-statistic: 17.97 on 1 and 9 DF, p-value: 0.002179

summary(lm_x3y3)

Call: lm(formula = data\(y3 ~ data\)x3)

Residuals: Min 1Q Median 3Q Max -1.1586 -0.6146 -0.2303 0.1540 3.2411

Coefficients: Estimate Std. Error t value Pr(>|t|)
(Intercept) 3.0025 1.1245 2.670 0.02562 * data$x3 0.4997 0.1179 4.239 0.00218 ** — Signif. codes: 0 ‘’ 0.001 ’’ 0.01 ’’ 0.05 ‘.’ 0.1 ‘’ 1

Residual standard error: 1.236 on 9 degrees of freedom Multiple R-squared: 0.6663, Adjusted R-squared: 0.6292 F-statistic: 17.97 on 1 and 9 DF, p-value: 0.002176

summary(lm_x4y4)

Call: lm(formula = data\(y4 ~ data\)x4)

Residuals: Min 1Q Median 3Q Max -1.751 -0.831 0.000 0.809 1.839

Coefficients: Estimate Std. Error t value Pr(>|t|)
(Intercept) 3.0017 1.1239 2.671 0.02559 * data$x4 0.4999 0.1178 4.243 0.00216 ** — Signif. codes: 0 ‘’ 0.001 ’’ 0.01 ’’ 0.05 ‘.’ 0.1 ‘’ 1

Residual standard error: 1.236 on 9 degrees of freedom Multiple R-squared: 0.6667, Adjusted R-squared: 0.6297 F-statistic: 18 on 1 and 9 DF, p-value: 0.002165

“Statistical summary outputs from the 4 models are almost identical.Using the values of R-squared or Adjusted R-squared to determine the fitness of the model, we found that all 4 models showed almost the same fitness values: R-squared of 0.67 and Adjusted R-squared of 0.63”

  1. In text, summarize the lesson of Anscombe’s Quartet and what it says about the value of data visualization.

“Models with the same statistical output might not be derived from same datasets as they could come from different datasets.Therefore, looking only at the summary of statistical values might not be enough to make such conclusion. Data visualization, such as plotting graphs, could improve the understanding and help determine the relationship and distribution of the data in each model’s dataset in addition to just statistical values.”