Chapter 7 SUM OF CONTINUOUS RANDOM VARIABLES

Exercise 9: Assume that the service time for a customer at a bank is exponentially distributed with mean service time 2 minutes. Let X be the total service time for 10 customers. Estimate the probability that X > 22 minutes.

Mean Service time E(X) = 2 min.

\[E(X) = 1/\lambda = 2\]

So, \[\lambda = 2\]

\[ P(X>22) = e^{(-22\lambda)} \]

\[ P(X>22) = e^{(-22/2)} \]

\[ P(X>22) = e^{(-11)} \]

X be the total service time for 10 customers

\[ P(X>22) = 1 - P(X < 22) \]

\[ = 1 - \int_{0}^{22} (1/2) e^{-x/2} dt\]

\[ = 1 - 1/2 \Bigg[ e^{-x/2} / (-1/2) \Bigg]_{0}^{22} \]

\[ = 1 + \Bigg[ e^{-x/2} \Bigg]_{0}^{22} \] \[ = 1 + e^{-11} - e^{0} \]

exp(-11)
## [1] 1.67017e-05