Administration Items
- Homework 1 is due Next Monday!
- Today, we are covering Probability, Hypothesis, and Research Methods (briefly!)
- You will have lab time again to work on your homework….keep working on it :)
- Next Week: Chapters 7 and 8 :)
- Keep working on the research part of your drafts.
Probability Key Concepts
- Experiment: process by which an observation (or measurement) is obtained.
- Simple Event: the outcome that is observed on a single repetition of the experiment.
- Event: collection of simple events.
- Mutually Exclusive: when one event occurs, the other cannot, and vice versa.
- S: set of all simple events.
- Probability of an event A is equal to the sum of the simple events contained in A.
- The union of events A and B, denoted by \(A \cup B\) = either A or B occurring.
- The intersection of events A and B, denoted by \(A \cap B\) = BOTH A AND B OCCUR.
- The complement of an event A = \(A^C\) … where A does not occur!
- Independent: Two events, A and B, are said to be independent if and only if the probability of event B is not influenced or changed by the occurrence of event A, or vice versa.
- Random Variable: A variable x is a random variable if the value that it assumes, corresponding to the outcome of an experiment, is a chance or random event.
- Experiment: process by which an observation or measurement is obtained.
Probability
- In previous Chapters we introduced topics such as qualitative (Nominal and Ordinal) and quantitative (Interval and Ratio) variables. Today, we are talking about Discrete Random Variables and Their Probability Distributions.
- However, even qualitative variables can generate numerical data if the categories are numerically coded to form a scale. For example, if you toss a single coin, the qualitative outcome could be recorded as “0” if a head and “1” if a tail.
- We can record outcomes and describe the results using probability and statistics.
Concepts
An experiment is the process by which an observation or measurement is obtained.
Examples:
- Recording weight
- Recording vital signs in the E.R.
- Recording an opinion (yes or no)
- Toss two coins
- Values for a card
Simple Events
These are the outcomes that are observed on a single repetition of the experiment. We can use a deck of cards to record values for probability and statistical purposes :)
- The basic element to which probability is applied.
- One and only one simple event can occur when the experiment is performed.
A simple event is denoted by E with a subscript. \(E_a\).
Each simple event will be assigned a probability, measuring “how often” it occurs. The set of all simple events of an experiment is called the sample space, S.
TOSSING A COIN
\(E_{Head}\) |
number |
\(E_{Tail}\) |
number |
S = {\(E_{Head}\), \(E_{Tail}\)}
Events
A collection of simple events. For example a deck of cards.
- \(\heartsuit\) Hearts: King, Queen, Jack, 10, 9, 8, 7, 6, 5, 4, 3, 2, Ace
- \(\clubsuit\) Clubs: King, Queen, Jack, 10, 9, 8, 7, 6, 5, 4, 3, 2, Ace
- \(\spadesuit\) Spades: King, Queen, Jack, 10, 9, 8, 7, 6, 5, 4, 3, 2, Ace
- \(\diamondsuit\) Diamonds: King, Queen, Jack, 10, 9, 8, 7, 6, 5, 4, 3, 2, Ace
Total Cards = 52 (26 Black and 26 Red)
Basic probability without replacement for a red queen (think Alice in Wonderland):

P(Red) = 26/52 or ½ , P(Queen) is 4/52 or 1/13 so P(Red and Queen) = ½ * 1/13 = 1/26
The Probability of an Event
The probability of an event A is found by adding the probabilities of all the simple events contained in A.
- We can find probabilities by using:
- Estimates from empirical studies
- Common sense estimates based on equally likely events
- Coin Toss: P(Head) = 1/2 = .50 = 50%
- 10% of a sample have red hair: P(Red Hair) = 10% = .10
For this class
You will not be required to know probability theory, rather, you will be asked to engage in probability techniques through statistical analysis. This is a back story. Statistics is built on the probability that your hypotheses are set up in such a way, that you can see the probability that you accept or reject the null in favor of the alternative.
Brief Example
In a certain population, 10% of the people can be classified as being high risk for a heart attack. Three people are randomly selected from this population. What is the probability that exactly one of the three are high risk?
- Let P = Probability and Set up definitions:
- H = high risk and N = not high risk
- Set up the events:
- Math: P(H) + P(N) = 1.0 –> .10 + .90 = 1.00 :)
- P(exactly one high risk) = P(HNN) + P(NHN) + P(NNH)
- = P(H)P(N)P(N) + P(N)P(H)P(N) + P(N)P(N)P(H)
- = (.1)(.9)(.9) + (.9)(.1)(.9) + (.9)(.9)(.1)= 3(.1)(.9)2 = .243
- Answer: 0.243
Next Week
- Homework one is due: 9/29/14 Monday
- Chapter 7: Statistical Inference
- Chapter 8: Probability – z and t test
- Keep working on your writing drafts…research and documentation
- Homework two will be released on 10/06
- Midterm exam: 10/22/14