Assignment #11

shelf1=c(10,6,1,3,2,11,15,10,11,6,2,3,0,0,0,3,3,3,8)

median(shelf1)

## [1] 3

mean(shelf1)

## [1] 5.105

hist(shelf1,
     col="red",
     main="Shelf 1",
     xlab="Sugar Content in Cereal")

The graph is skewed to the right. The mean is at 5.1 which makes sense because thats in the middle of the graph. The median is at 3 which is where a lot of the data lies in just a few bars on the left of the graph. The median is the middle number in a data set do if there is a large frequency of one number then the median is close to that number.

shelf2=c(14,12,9,13,12,13,0,13,7,12,9,11,3,6,12,3,9,12,15,5,12)

median(shelf2)

## [1] 12

mean(shelf2)

## [1] 9.619

hist(shelf2,
     col="green",
     main="Shelf 2",
     xlab="Sugar Content in Cereal")

This graph is skewed to the left. The mean is at 9.6 sugar content which makes sense because the shelf 2 is closer to the reach of kids and is going to have more kinds of cereal with high amounts of sugar.The median is 12 which is where a majority of the data lies.

shelf3=c(6,8,5,0,8,8,5,7,7,3,10,5,10,5,3,4,6,9,1,1,13,7,2,10,14,3,0,0,6,8,6,14,3,3,12)

median(shelf3)

## [1] 6

mean(shelf3)

## [1] 6.057

hist(shelf3,
     col="purple",
     main="shelf 3",
     xlab="Sugar Content in Cereal")

This graph has almost an uniform shape. The mean is at 6 which is almost completely in the middle of the graph which shows there wasn’t a huge variation in the frequencys of the cereal for each different sugar level.The median is 6 which is very close to the middle of the graph which again shows there wasn’t a huge variation of the data.