1.
t0.01=2.602
-t0.05=-1.73
+/-t0.025=+/-2.18
2.
t0.1=1.321
-t0.01=-2.43
+/-0.005=+/-2.74
3.
t0=-1.38
-t0.05=-1.714
skip
the test statistic is greater than the critical value, so there is not enough evidence for the researcher to reject the null hypothesis
4.
t0=2.674
t0.1=1.32
skip
reject the null hypothesis because it is a right tailed test with a test stastic greater than the critical value
5.
t0=2.502
-t0.005=-2.819; t0.005=2.819
skip
there is not enough evidence to reject
lower:99.4 ;upper:110.2; do not reject the null hypothesis
11.
Ho: mu=$67
H1: mu>$67
0.02 probability of obtaining a sample mean greater than $73. if 100 random samples of 40 were taken from a population with a mean of 67 then only 2 samples would be above $73
reject the null hypothesis because the p-value is low
13.
Ho: mu=22
H1: mu>22
the scores are independent because the sample is random and the size is large
classical, t0=2.18>t0.05=1.66;p-value, 0.01<p-value<0.02; both reject the null hypothesis
there is enough evidence to claim that students who complete core curriculum score above a 22 on the ACT
15.
p-value<0.0005<alpha=.01; reject the null hypothesis
17.
0.25>p-value>0.20>alpha=.05; do not reject the null hypothesis
19.
(35.44, 42.36), not enough information to conclude that the mean age has changed
1.
x^2 0.05=28.87
x^2 0.9=14.04
x^2 0.975=16.047; x^2 0.025=83.3
3.
x^2 0=20.5
x^2 0.95=13.1
Skip but feel free to sketch on a piece of paper for your benefit.
do not reject null hypothesis
13. Feel free to use any method you want. If you use the classical method please report the value of your test statistic and your decision. Likewise if you use the pvalue method please state your pvalue and your decision. Hint: The sample standard deviation (s) is 15.20.
0.10<p-value<0.90; do not reject null hypothesis
15. Feel free to use any method you want. If you use the classical method please report the value of the test statistic and your decision. Likewise if you use the pvalue method please state your pvalue and your decision.
0.05<p-value<0.10; reject the null hypothesis