9.
Right tailed, mew
10.
left tailed, p
11.
two tailed, standard deviation
12.
right tailed, p
13.
left tailed, mew
14.
two tailed, standard deviation
15.
Ho: p = 0.399
H1: p > 0.399
17.
Ho: mew = $245,700
H1: mew < $245,700
19.
Ho: standard deviation = 0.7 psi
H1: standard deviation < 0.7 psi
21.
Ho: mew = $48.79
H1: mew =/ $48.79
7.
9.
11.
13.
The p value of 0.2743 means that if the null hypothesis is true, this type of result would be expected in about 27-28 of out every 100 samples. Because the p value is so large, do not reject the null hypothesis.
15. Note this is slightly modified version of the book problem Just answer a) b) and c) fromt the skeleton.
320/678 = 0.472
Ho: p = 0.5
H1: p < 0.5
17.
p value = 0.2582
Do not reject the null hypothesis.
19.
p value = 0.0036
Since 0.0036 < 0.05, reject the null hypothesis