Dingxian Cao, Peiyang Yu
Geometric Brownion Motion\[ dS_{t}=\mu S_{t}\,dt+\sigma S_{t}\,dW_{t}\\dlog(S_t)=(\mu -\frac{1}{2}\sigma^2)dt + \sigma dW_t \] In our problem: \( \sigma \rightarrow \sigma_t \)
\[ \begin{array}{aligned} d log(s_t) = (θ_1 + θ_2σ_t^2)dt + σ_tdB_t \\ dv_t = μv_tdt + ξv_tdB_t \\ R = log(s_T /s_0) \\ \bar v = (1/T)\int_0^T v_τdτ \end{array} \]
a. Diffusion process is a solution to a stochastic differential equation.
b. Diffusion Process is a continuous Markov Process.
c. Use a SDE to infer a underlying diffusion process.
d. The mean variance is an integral of square volatility over the path.
A result:
When ρ = 0, f(R|\( \bar v \)) = \( N(η,λ^2) \),
\( η = (θ_1 + θ_2 \bar v)T~~ and~~ λ^2 = T\bar v \),
Problem:
How to derive f(\( \bar v \) | R=r).
Price \( \{s_t\} \) model:
\[ d log(s_t) = (θ_1 + θ_2σ_t^2)dt + σ_tdB_t \]
Volatility \( \{v_t\} \) model:
\[ dv_t = μv_tdt + ξv_tdB_t \]
mean variance: \( \bar v = (1/T)\int_0^T v_τdτ \)
Goal: \( f(\bar v|R=r) \)
Data: R=r,
likelihood function: \( \phi(r,η(\bar v),λ^2(\bar v)) \)
p.s. model fitting issues.
Standard and Poor’s 500 index (S&P 500) from 5/5/1995 to 14/4/2003.
\[ \begin{array}{aligned} d log(s_t) = (θ_1 + θ_2σ_t^2)dt + σ_tdB_t \\ dv_t = θ_4(θ_5 − v_t)dt + θ_3v_tdw_t. \end{array} \]
(θ2,θ4)=0 and \( (θ_1 , θ_3^2 , θ_5 , ρ) \) = (0.022, 0.029, 3.09, -0.84).
\( E(\bar v|r) \) are (0.012, 0.0139, 0.0144) for r = (0.039, 0.05,0.055)
\[ Thank~~You \]