3.1

13 type answers mean:(34.0+33.2+37.0+29.4+23.6+25.9)/6＝30.52mpg median:(29.4+33.2)／2=31.3mpg no mode for this set of data 14 type answers mean:(60.5+128.0+84.6+122.3+78.9+94.7+85.9+89.9)/8=93.1min median:(89.9+85.9)/2=87.9 there is no mode for this set of data 15 type answers mean:(3960+4090+3200+3100+2940+3830+4090+4040+3780)/9=3670psi median: 3830psi mode:4090psi 16 type answers mean: (282+270+260+266+257+260+267)/7=266min median:266min mode: 260 min 17

  1. type answer the histogram is skewed to the right, suggesting that the mean is greater than the median.
  2. type answer the histogram is symmetric, suggesting that the mean is approximately equal to the median.
  3. type answer the histogram is skewed to the left, suggesting that the mean is less than the median.

3.2

5 type answer sample variance: 36 sample standard deviation:6 6 type answer sample variance:99.75 sample stand deviation: 9.99 7 type answer population variance:16 standard deviation:4 8 type answer population variance:64 standard deviation:8 9 type answer sample variance:196 sample deviation:14 10 type answer population variance:25 population deciation:5 14 type answer range:282-257=25 sample standard deviatino: 71 24

  1. 6 seconds

  2. the histogram is symmetric, so it is applicable.

  3. since 92 is two standard deviations below the mean and 116 is two standard deviation above the mean, the Empirical Rule predicts that approximatelly 95% of eruptions will fall witnin the range

  4. 40/44=90.9%

e)since 98 seconds is one standard deviation below the mean, 4.7+27=31.7%

f)6/44=13.6%