means<-numeric(100)
minimums<-numeric(100)
for (i in 1:100)
{
#Exponential distribution
population <- rexp(30)
means[i]<-mean(population)
minimums[i]<-min(population)
}
hist(means)
This graph looks normally distributed.
hist(minimums)
The histogram is looks right-skewed because a larger percent of the values are located on the lower tail.