Statistical Reference Quiz 1
1. Consider influenza epidemics for two parent heterosexual families. Suppose that the probability is 17% that at least one of the parents has contracted the disease. The probability that the father has contracted influenza is 12% while the probability that both the mother and father have contracted the disease is 6%. What is the probability that the mother has contracted influenza?
# A=Mother, B = Father
# P(AuB)=17%, P(B)=12%, P(AnB)=6%.
# Since we know P(AuB)=P(A)+P(B)-P(AnB), therefore P(A)=P(AuB)-P(B)+P(AnB)
P_AuB <- 0.17
P_B <- 0.12
P_AnB <- 0.06
P_A <- P_AuB - P_B + P_AnB
P_A
## [1] 0.11
3. You are playing a game with a friend where you flip a coin and if it comes up heads you give her X dollars and if it comes up tails she gives you Y dollars. The probability that the coin is heads is p (some number between 0 and 1.) What has to be true about X and Y to make so that both of your expected total earnings is 0. The game would then be called “fair”.
# p/(1-p)=Y/X
5. Consider the following PMF shown below in R
x <- 1:4
p <- x/sum(x)
temp <- rbind(x, p)
rownames(temp) <- c("X", "Prob")
temp
## [,1] [,2] [,3] [,4]
## X 1.0 2.0 3.0 4.0
## Prob 0.1 0.2 0.3 0.4
mean <- sum(x*p)
mean
## [1] 3
6. A web site for home pregnancy tests cites the following: When the subjects using the test were women who collected and tested their own samples, the overall sensitivity was 75%. Specificity was also low, in the range 52% to 75%. Assume the lower value for the specificity. Suppose a subject has a positive test and that 30% of women taking pregnancy tests are actually pregnant. What number is closest to the probability of pregnancy given the positive test?
Bayes’ rule states that: P(A|B) = P(B|A)*P(A) / P(B)
P(+|Preg) = 0.75
P(+|NotPreg) = 1 - 0.52 = 0.48
P(Preg) = 0.3
P(NotPreg) = 1- 0.3 = 0.7
The unconditional probability of being found positive P(+)
P(+) = P(+|Preg) x P(Preg) + P(+|NotPreg) x P(NotPreg) = 0.75 x 0.3 + 0.48 x 0.7 = 0.561
P(Preg|+) = P(+|Preg) x P(Preg) / P(+|Preg) = 0.75 x 0.3 / 0.561 = 0.40